5. √(x²y³ – √x) dy, C is the arc of the curve y = √x from (1, 1) to (4, 2)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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James Stewart - Calculus_Early TX +
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16.2 Exercises
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2. xy ds,
1-16 Evaluate the line integral, where C is the given curve.
1. fey³ds, C: x= t³, y=t, 0 ≤ t ≤2
C: x= t², y = 2t, 0≤te]
-
3.xyds, C is the right half of the circle x² + y² = 16
4.
x siny ds, C is the line segment from (0, 3) to (4, 6)
5. (x²y³ -√√x) dy,
C is the arc of the curve y = √√x from (1, 1) to (4,2)
6. e* dx,
C is the arc of the curve x = y³ from (-1,-1) to (1, 1)
7. (x + 2y) dx + x² dy, C consists of line segments from
(0, 0) to (2, 1) and from (2, 1) to (3, 0)
8. x² dx + y² dy, C consists of the are of the circle
x² + y² = 4 from (2, 0) to (0, 2) followed by the line segment
from (0, 2) to (4,3)
Graphing calculator or computer required
CAS Computer algebra sys
Q Search
b
Transcribed Image Text:↓ Q James Stewart - Calculus_Early TX + ㅌㅂ. File C:/Users/Kervi/Downloads/James%20Stewart%20-%20Calculus_%20Ea Draw 16.2 Exercises Read aloud 2. xy ds, 1-16 Evaluate the line integral, where C is the given curve. 1. fey³ds, C: x= t³, y=t, 0 ≤ t ≤2 C: x= t², y = 2t, 0≤te] - 3.xyds, C is the right half of the circle x² + y² = 16 4. x siny ds, C is the line segment from (0, 3) to (4, 6) 5. (x²y³ -√√x) dy, C is the arc of the curve y = √√x from (1, 1) to (4,2) 6. e* dx, C is the arc of the curve x = y³ from (-1,-1) to (1, 1) 7. (x + 2y) dx + x² dy, C consists of line segments from (0, 0) to (2, 1) and from (2, 1) to (3, 0) 8. x² dx + y² dy, C consists of the are of the circle x² + y² = 4 from (2, 0) to (0, 2) followed by the line segment from (0, 2) to (4,3) Graphing calculator or computer required CAS Computer algebra sys Q Search b
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