5. Why is it important that your glassware be dry for Part 2? Postulate as to what would have happened (i.e. how would your results have differed) if you had used water as your solvent in Part 2?
5. Why is it important that your glassware be dry for Part 2? Postulate as to what would have happened (i.e. how would your results have differed) if you had used water as your solvent in Part 2?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need help with the second part of the question. What would happen if we used water as a solvent. How is it supported with my observations? My observations for this portion were as follows: the cobalt did not dissolve immediately, when the ethanol was added there is a purple/pink coloration, after a few seconds the cobalt turned blue/dark blue, finally as it is completely dissolved it turned dark purple with blue undertones.
Transcribed Image Text:**Question 5**: Why is it important that your glassware be dry for Part 2? Postulate as to what would have happened (i.e. how would your results have differed) if you had used water as your solvent in Part 2?
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This question emphasizes the significance of using dry glassware in a scientific experiment, particularly Part 2 of a procedure. It invites discussion on the potential impact of using water as a solvent, suggesting that the presence of moisture could alter the experimental results.
![**Chemical Equation:**
\[ \text{Co}(\text{H}_2\text{O})_6^{2+} + 2\text{Cl}^- \rightleftharpoons \text{CoCl}_2(\text{H}_2\text{O})_2 + 4\text{H}_2\text{O} \]
**Description:**
- **Reactants:**
- \(\text{Co}(\text{H}_2\text{O})_6^{2+}\): A cobalt complex ion with six water molecules.
- \(2\text{Cl}^-\): Two chloride ions.
- **Products:**
- \(\text{CoCl}_2(\text{H}_2\text{O})_2\): A cobalt chloride complex with two water molecules.
- \(4\text{H}_2\text{O}\): Four water molecules released.
**Reaction Type:** Equilibrium reaction, indicated by the reversible arrow (\(\rightleftharpoons\)).
**Notes:**
- This chemical equation represents the equilibrium between two cobalt complexes.
- System I (\(\text{Co}(\text{H}_2\text{O})_6^{2+}\)) is initially surrounded by more water molecules, while System II (\(\text{CoCl}_2(\text{H}_2\text{O})_2\)) has chloride ions partially substituting the water molecules.
**Application in Education:**
- This equation can illustrate concepts such as coordination chemistry, complex ions, and equilibrium reactions in a classroom or textbook setting.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc45a61cd-259f-4034-96ab-adfb5c1cf9d8%2F5ffddbb1-0faa-49a1-90cd-e475f9146d47%2F22lfu3s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Chemical Equation:**
\[ \text{Co}(\text{H}_2\text{O})_6^{2+} + 2\text{Cl}^- \rightleftharpoons \text{CoCl}_2(\text{H}_2\text{O})_2 + 4\text{H}_2\text{O} \]
**Description:**
- **Reactants:**
- \(\text{Co}(\text{H}_2\text{O})_6^{2+}\): A cobalt complex ion with six water molecules.
- \(2\text{Cl}^-\): Two chloride ions.
- **Products:**
- \(\text{CoCl}_2(\text{H}_2\text{O})_2\): A cobalt chloride complex with two water molecules.
- \(4\text{H}_2\text{O}\): Four water molecules released.
**Reaction Type:** Equilibrium reaction, indicated by the reversible arrow (\(\rightleftharpoons\)).
**Notes:**
- This chemical equation represents the equilibrium between two cobalt complexes.
- System I (\(\text{Co}(\text{H}_2\text{O})_6^{2+}\)) is initially surrounded by more water molecules, while System II (\(\text{CoCl}_2(\text{H}_2\text{O})_2\)) has chloride ions partially substituting the water molecules.
**Application in Education:**
- This equation can illustrate concepts such as coordination chemistry, complex ions, and equilibrium reactions in a classroom or textbook setting.
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