5. What would the voltage be at the following times if the initial voltage is 8V, the resistance is 2 kf2 and the capacitance is 50 µF. (a) At t=0 ms, V (b) At t-100 ms, V= (c) At t-1000 ms, V=

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5. What would the voltage be at the following times if the initial voltage is 8V, the resistance is 2 kf? and
the capacitance is 50 pF.
(a) At t=0 ms, V
(b) At t-100 ms, V=
(c) At t-1000 ms, V=
Transcribed Image Text:5. What would the voltage be at the following times if the initial voltage is 8V, the resistance is 2 kf? and the capacitance is 50 pF. (a) At t=0 ms, V (b) At t-100 ms, V= (c) At t-1000 ms, V=
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Follow-up Question
5. What would the voltage be at the following times if the initial voltage is 8V, the resistance is 2 k and
the capacitance is 50 pF.
a) At t=0 ms, V =
Ov 8V
(b) At t=100 ms, V=_S.TV
At t=1000 ms, V=
8V
V = V₁ (1-e #2) -> (8) 11-e²c ) = Uv
-100 x10-3
0 (50x10x)) = -5.0STV
v = (8) 11-e | 2000 (50x100
-1000103
V= (8) 11- 2000 (Sux/0-4)
2
8.00
Transcribed Image Text:5. What would the voltage be at the following times if the initial voltage is 8V, the resistance is 2 k and the capacitance is 50 pF. a) At t=0 ms, V = Ov 8V (b) At t=100 ms, V=_S.TV At t=1000 ms, V= 8V V = V₁ (1-e #2) -> (8) 11-e²c ) = Uv -100 x10-3 0 (50x10x)) = -5.0STV v = (8) 11-e | 2000 (50x100 -1000103 V= (8) 11- 2000 (Sux/0-4) 2 8.00
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Follow-up Question
5. What would the voltage be at the following times if the initial voltage is 8V, the resistance is 2 k and
the capacitance is 50 uF.
You
At t=0 ms, V =
Ov 8V
(b) At t=100 ms, V=_S.SV
At t=1000 ms, V=
8V
V = Vu (1-22)-> (8)(1-eft) = uv
-100
v = (8) 11-e (2000 (50x10²4)) -- S.USTV
-1000103 +0₁) = 8.00
V= (8) (1-e 2000 (Saxiy
2
0
Transcribed Image Text:5. What would the voltage be at the following times if the initial voltage is 8V, the resistance is 2 k and the capacitance is 50 uF. You At t=0 ms, V = Ov 8V (b) At t=100 ms, V=_S.SV At t=1000 ms, V= 8V V = Vu (1-22)-> (8)(1-eft) = uv -100 v = (8) 11-e (2000 (50x10²4)) -- S.USTV -1000103 +0₁) = 8.00 V= (8) (1-e 2000 (Saxiy 2 0
Solution
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Follow-up Question
5. What would the voltage be at the following times if the initial voltage is 8V, the resistance is 2 ks and
the capacitance is 50 μF.
Ya
At t=0 ms, V = OV 8V
(b) At t=100 ms, V=_S.SV
Y) At t=1000 ms, V=
8V
V = Vu (1-22)-> (8) 11-e²²c ) = 0 v
- 100
v = (8) 11-e ( 2000 (50x10²4) -- S.OSTV
-10003103
V= (8) 11- 2000 (Saxi
2
= 8.00
Transcribed Image Text:5. What would the voltage be at the following times if the initial voltage is 8V, the resistance is 2 ks and the capacitance is 50 μF. Ya At t=0 ms, V = OV 8V (b) At t=100 ms, V=_S.SV Y) At t=1000 ms, V= 8V V = Vu (1-22)-> (8) 11-e²²c ) = 0 v - 100 v = (8) 11-e ( 2000 (50x10²4) -- S.OSTV -10003103 V= (8) 11- 2000 (Saxi 2 = 8.00
Solution
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