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Two capacitors are connected in series combination. C = 11 µF and C2 = 20 µF. Both capacitors have a breakdown voltage of 15 V. What is the breakdown voltage of the combination? V

Two capacitors are connected in series combination. C = 11 µF and C2 = 20 µF. Both capacitors have a breakdown voltage of 15 V. What is the breakdown voltage of the combination? V

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Two capacitors are connected in series combination. \( C_1 = 11 \, \mu \text{F} \) and \( C_2 = 20 \, \mu \text{F} \). Both capacitors have a breakdown voltage of 15 V. What is the breakdown voltage of the combination? [Input box for answer] V
Transcribed Image Text:Two capacitors are connected in series combination. \( C_1 = 11 \, \mu \text{F} \) and \( C_2 = 20 \, \mu \text{F} \). Both capacitors have a breakdown voltage of 15 V. What is the breakdown voltage of the combination? [Input box for answer] V
Expert Solution
Concept and Principle:

Capacitors can be connected in series or parallel combinations when they are connected in series the amount of charge on each capacitor will remain unchanged. Using this it is possible to find the ratio of voltage on both capacitors.

Charge on a capacitor is given by,

V=QC

In a series combination, the voltage will add up. So,

V=V1+V2

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