5. What is the conventional cell notation for the Cu/Pb voltaic cell in prepared in question 3b, assuming the half cells are connected by a salt bridge?
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![4. What is the % difference between the experimental voltage (Eexpt) measured for the Cu/Zn voltaic
cell (see lab lecture pictures) and the expected voltage (Etheo)? Based on the discussion in the lab
manual, give a reason for this difference.
5. What is the conventional cell notation for the Cu/Pb voltaic cell in prepared in question 3b,
assuming the half cells are connected by a salt bridge?
6. The measured voltage, Eexpt, for the Pb/Zn cell (see lab lecture pictures) was significantly different
from the expected voltage calculated in question 3c above. What is the best explanation for this
difference?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc446e82b-4418-4788-92f7-18f3b38381a9%2F2814d77e-02a9-4c83-85d4-9f885788314f%2F5uv7tsp_processed.jpeg&w=3840&q=75)
![Cumbde-Cue +2e- CU
(ag)
+U. 16
+0.34
cell
E= 1.10-8.314 299.65 en [O.o500]
96485
[0.0400]
1,094V
%3D
theo
6.0.0400M CUSO cog) and 00300M Po(NO)lag)
Anode-Pds Po"(a9)+2e- Eeu
Cathade= Cu2t +2e->Cu
Pols) + Cuz(ag) → Po+ Cu(s)
0.0300M
0.47
0.0Y00M
8.314~299.65
96485
Thes
F047-(8.314-299.05
en/0.03
0.04
=0.47+0.007406](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc446e82b-4418-4788-92f7-18f3b38381a9%2F2814d77e-02a9-4c83-85d4-9f885788314f%2F8kersbf_processed.jpeg&w=3840&q=75)
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