**Question:**5. What digital logic does the following circuit represent? Explain your answer with the analog truth table. Assume \( V_1 = V_2 = 5V \), the BJT transistors work in saturation and \( V_{CE(sat)} = 0.2V \) (for both).**Diagram Explanation:**The circuit diagram shows a transistor-based logic circuit with two Bipolar Junction Transistors (BJTs), \( Q_1 \) and \( Q_2 \), configured in a cascaded arrangement. The key components include:- Two input voltages, \( V_1 \) and \( V_2 \), are applied at the bases of the transistors \( Q_1 \) and \( Q_2 \) through identical base resistors \( R_B \).- Each transistor has a collector resistor, \( R_C \), connected to a common supply voltage \( V_{CC} = 5V \).- The emitters of both transistors are connected to the ground.- The output voltage, \( V_O \), is taken from the connection between the collector of \( Q_2 \) and \( R_C \).In this circuit, the transistors are in saturation mode, meaning they conduct fully when a base current is applied, allowing maximum current through the collector-emitter path.**Logic Analysis:**This circuit operates as a NAND gate. In a NAND gate:- The output is high (\( V_{CC} \)) when at least one of the inputs is low (0V).- The output is low (close to 0V) only when both inputs are high.**Truth Table:**| \( V_1 \) | \( V_2 \) | \( V_O \) ||-----------|-----------|-----------|| 0 | 0 | 5V || 0 | 1 | 5V || 1 | 0 | 5V || 1 | 1 | 0.2V |In conclusion, when both \( V_1 \) and \( V_2 \) are high (5V), both transistors saturate, causing the output \( V_O \) to be low (~0.2V). For all other input combinations, the output remains high at 5V. Thus, this circuit functions as a NAND

Given:A digital logic circuit,when V1=V2=5 V (high logic), both transistors work in saturation and V(sat) = 0.2 V.we need to find:what does this logic circuit represent?when input to the transistor is 0 V (logic low), the transistor is in cutoff mode. when input to the transistor is 5 V (logic high), the transistor is in saturation mode with Vsat = 0.2 V.So using above concept we can develop analogue truth table as, V1V2V00 V (Logic low)0 V (Logic low)5 V (Logic high)0 V (Logic low)5V (Logic high)0.2 V (Logic low)5 V (Logic high)0 V (Logic low)0.2 V (Logic low)5 V (Logic high)5V (Logic high)0.2 V (Logic low) and hence we can make digital truth table as, V1V2V0001010100110From above table, it is clear that logic circuit is "NOR gate".The given logic circuit is "NOR gate".

Engineering

Electrical Engineering

5. What digital logic does the following circuit represent? Explain your answer with the analog truth table. Assume V₁ = V2 = 5V, the BJT transistors work in saturation and VCE(sat)= 0.2V (for both). RB V₁ww IBI Vcc=5 V Rc IC Q₁ V₂0 RB Ic₂ 0₂ Vo

5. What digital logic does the following circuit represent? Explain your answer with the analog truth table. Assume V₁ = V2 = 5V, the BJT transistors work in saturation and VCE(sat)= 0.2V (for both). RB V₁ww IBI Vcc=5 V Rc IC Q₁ V₂0 RB Ic₂ 0₂ Vo

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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