Can you please help with: d) Explain why i2(0−) !=i2(0+).e) Find i1(t) for t ≥ 0.f) Find i2(t) for t ≥ 0+ . 5. The switch in the figure below has been open for a long time and closes at time t = 0. a) Find ii (0) andi2(0). b) Find i1₁ (0+) and i2(0+). c) Explain why i₁(0) = ₁ (0+). d) Explain why i2(0−) !=i2(0+). e)Find i₁(t) for t≥ 0. f) Find i2(t) for t 20+3μF1V150mA1202M6026ΩΝ 12Xt=0802w2130

For the given RC circuit, we need to determine:(a) i1(0−) and i2(0−),(b) i1(0+) and i2(0+),(c) explain why i1(0−)=i1(0+),(d) explain why i2(0−)≠i2(0+), (e) i1(t) ∀ t≥0, and(f) i2(t) ∀ t≥0.For time just before closing the switch, the capacitor is in steady-state, i.e., open-circuited, as shown below.We apply nodal analysis at node A.The initial currents areThe initial capacitor voltage isAt the switch closes, and it creates a short-circuited path. We know that the voltage across the capacitor does not change simultaneously. Hence, V.The voltage across resistor is the capacitor voltage. Its current isThe current through resistor isThe equivalent resistance seen by the capacitor isThe time-constant of the circuit isWe can see that the steady-state voltage across the capacitor will be zero as there is no source present in the active path of the capacitor circuit. Hence, V.The capacitor voltage equation for time isThe current through isThe current through resistor is The current through the resistor remains constant after the switch is closed because it is connected across the capacitor, and the voltage of the capacitor does not change simultaneously.The current through the resistor is not constant because the voltage across it is changed.