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5. The drill shaft of an oil well is made of A992 steel (E = 29000 ksi). The shaft extends 1200 ft into the ground and hangs freely from the derrick at A. Sketch the variation of the axial force in the pipe along the length in an axial load diagram. Calculate the maximum stress in each section of pipe and find the elongation of end D with respect to A. Note the weight per foot of the pipe is listed in the diagram.

5. The drill shaft of an oil well is made of A992 steel (E = 29000 ksi). The shaft extends 1200 ft into the ground and hangs freely from the derrick at A. Sketch the variation of the axial force in the pipe along the length in an axial load diagram. Calculate the maximum stress in each section of pipe and find the elongation of end D with respect to A. Note the weight per foot of the pipe is listed in the diagram.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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5. The drill shaft of an oil well is made of A992 steel (E = 29000 ksi). The shaft extends 1200 ft into the ground and hangs freely from the derrick at A. Sketch the variation of the axial force in the pipe along the length in an axial load diagram. Calculate the maximum stress in each section of pipe and find the elongation of end D with respect to A. Note the weight per foot of the pipe is listed in the diagram. AB=2.50 in.² WAB=3.2 lb/ft ABC= 1.75 in2 WBC= 2.8 lb/ft Acp= 1.25 in? WCD=2.0 lb/ft B 1 C 5000 ft D 5000 ft 2000 ft
Transcribed Image Text:5. The drill shaft of an oil well is made of A992 steel (E = 29000 ksi). The shaft extends 1200 ft into the ground and hangs freely from the derrick at A. Sketch the variation of the axial force in the pipe along the length in an axial load diagram. Calculate the maximum stress in each section of pipe and find the elongation of end D with respect to A. Note the weight per foot of the pipe is listed in the diagram. AB=2.50 in.² WAB=3.2 lb/ft ABC= 1.75 in2 WBC= 2.8 lb/ft Acp= 1.25 in? WCD=2.0 lb/ft B 1 C 5000 ft D 5000 ft 2000 ft
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