5. The dichromate ion, Cr2O72- reacts with methanol, CH3OH in acidic solution according to the equation below. If 200.0 mL of 1.00 M Cr20,2 (aq) reacts with 200.0 mL of 1.875 M CH3OH (aq) in the presence of 200.0 mL of 10.0 M H* (aq), show how you determine (a) the limiting reagent and moles of each of the two excess reagents left at the end of the reaction [Hint: H* is one of the excess reagents!]; (b) the number of moles & grams of all products expected to form; and (c) the molar concentration of each type of aqueous species present in the final mixture. The balanced chemical equation is 2 Cr207-(aq) + 3 CH3OH (aq) + 16 H*(aq) → 4 Cr³* (aq) + 3 HCO2H (ag) + 11 H20 ()

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5. The dichromate ion, Cr2072- reacts with methanol, CH3OH in acidic solution
according to the equation below. If 200.0 mL of 1.00 M Cr2O7?-(aq) reacts with 200.0
mL of 1.875 M CH3OH (aq) in the presence of 200.0 mL of 10.0 M H† (aq), show how
you determine
(a) the limiting reagent and moles of each of the two excess reagents left at the end of the
reaction [Hint: H* is one of the excess reagents!]; (b) the number of moles &
grams of all products expected to form; and (c) the molar concentration of each type
of aqueous species present in the final mixture. The balanced chemical equation is
2 Cr207 (aq) + 3 CH3OH (aq) + 16 H*(aq) → 4 Cr*(aq) + 3 HCO2H (aq) + 11 H2O (1)
Transcribed Image Text:Answers accurate to 3 or 4 significant figures & show your work. 5. The dichromate ion, Cr2072- reacts with methanol, CH3OH in acidic solution according to the equation below. If 200.0 mL of 1.00 M Cr2O7?-(aq) reacts with 200.0 mL of 1.875 M CH3OH (aq) in the presence of 200.0 mL of 10.0 M H† (aq), show how you determine (a) the limiting reagent and moles of each of the two excess reagents left at the end of the reaction [Hint: H* is one of the excess reagents!]; (b) the number of moles & grams of all products expected to form; and (c) the molar concentration of each type of aqueous species present in the final mixture. The balanced chemical equation is 2 Cr207 (aq) + 3 CH3OH (aq) + 16 H*(aq) → 4 Cr*(aq) + 3 HCO2H (aq) + 11 H2O (1)
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