5. Squaring both sides and substituting for i1 + ip2 = | gives ipi – 2/ipiiD2 + ip2 1 knT Vid 2 inim = I-;K, W 2 U jd %3D 2 6. Substituting for İ22 as ip2 = 1– ip1 and squaring both sides of the resulting equation provides a quadratic equation in i that can be solved to yield
5. Squaring both sides and substituting for i1 + ip2 = | gives ipi – 2/ipiiD2 + ip2 1 knT Vid 2 inim = I-;K, W 2 U jd %3D 2 6. Substituting for İ22 as ip2 = 1– ip1 and squaring both sides of the resulting equation provides a quadratic equation in i that can be solved to yield
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
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How to drive id1 and id2 the steps are written but I did not understand point 5 to the whole and I prefer to explain it for me by steps
![5. Squaring both sides and substituting for ip1 + ip2 = | gives
1
W 2
V id
W
ip1 – 2/ipiiD2 + ip2
kn7 Vid
6. Substituting for Ip2 as Ip2 = /- ip1 and squaring both sides of the resulting
equation provides a quadratic equation in i1 that can be solved to yield
W, ("id
Kn L
(v/2)
2.
W
I/ k,
(v/2)
1
(v ja/ 2)*
W
I/ K
W
1
2
W
k'n
%3D
%3D
W
I/ K,
W
2 2L
W
(Vos - V, = K,- Vov
Then, replace K,(W/L) by VVov
Since,
/2 2
ipi
Vov 2
1
Vov
ipz
Vov 2.
1.
Vov](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7540c4f1-3059-4df3-ac55-48d69e9c8c22%2F9398921c-a28b-4a93-97aa-48fe7c5f6dcf%2Fygxkk5f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. Squaring both sides and substituting for ip1 + ip2 = | gives
1
W 2
V id
W
ip1 – 2/ipiiD2 + ip2
kn7 Vid
6. Substituting for Ip2 as Ip2 = /- ip1 and squaring both sides of the resulting
equation provides a quadratic equation in i1 that can be solved to yield
W, ("id
Kn L
(v/2)
2.
W
I/ k,
(v/2)
1
(v ja/ 2)*
W
I/ K
W
1
2
W
k'n
%3D
%3D
W
I/ K,
W
2 2L
W
(Vos - V, = K,- Vov
Then, replace K,(W/L) by VVov
Since,
/2 2
ipi
Vov 2
1
Vov
ipz
Vov 2.
1.
Vov
![+Vom HANential inf
1. Expression drain currents for Q, and Q,.
1
W
İpi
Kn 7 (v GSI - V)
L.
W
(v GS2
-
%3D
2. Take the square roots of both sides of both equations
JiDi =
W
Kn7 (v CsI - V.)
Im =
W
K, (v cs2- V)
GS2
Q2
%D
I GS2
3. Subtract the two equations and perform
UGI
オVL
Vid
results in
22
W
Jim - Jim -
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7540c4f1-3059-4df3-ac55-48d69e9c8c22%2F9398921c-a28b-4a93-97aa-48fe7c5f6dcf%2Fmy7icl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:+Vom HANential inf
1. Expression drain currents for Q, and Q,.
1
W
İpi
Kn 7 (v GSI - V)
L.
W
(v GS2
-
%3D
2. Take the square roots of both sides of both equations
JiDi =
W
Kn7 (v CsI - V.)
Im =
W
K, (v cs2- V)
GS2
Q2
%D
I GS2
3. Subtract the two equations and perform
UGI
オVL
Vid
results in
22
W
Jim - Jim -
%3D
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