5. Nicotinamide adenine dinucleotide (NADH/NAD*) is a cofactor found in our cells! It is able to undergo reduction/oxidation reactions Cost HH vir o-P-0- NADH O O=P-C HH NH₂ OH OH OH OH NH₂ Nicotinamide adenine dicucleotide (NADH) The active portion of NADH is the nicotinamide nucleobase. It acts as a reducing agent because it is able to donate electrons in the form of a hydride. Shown below is the overall synthetic scheme of the oxidation of NADH to NAD*. NH₂ _nicotinamide adenine nucleobase H NAD+ NH₂ Explain why the oxidation of NADH to NAD* is a favorable reaction even though NAD* gains a charge?
5. Nicotinamide adenine dinucleotide (NADH/NAD*) is a cofactor found in our cells! It is able to undergo reduction/oxidation reactions Cost HH vir o-P-0- NADH O O=P-C HH NH₂ OH OH OH OH NH₂ Nicotinamide adenine dicucleotide (NADH) The active portion of NADH is the nicotinamide nucleobase. It acts as a reducing agent because it is able to donate electrons in the form of a hydride. Shown below is the overall synthetic scheme of the oxidation of NADH to NAD*. NH₂ _nicotinamide adenine nucleobase H NAD+ NH₂ Explain why the oxidation of NADH to NAD* is a favorable reaction even though NAD* gains a charge?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:5. Nicotinamide adenine dinucleotide (NADH/NAD*) is a cofactor found in our cells! It is able to
undergo reduction/oxidation reactions
Spot
o-p-o-
NADH
O
O=P-O
HH
ģe
N
vir
OH OH
N
NH₂
ОН OH
NH₂
NH₂
Nicotinamide adenine dicucleotide (NADH)
The active portion of NADH is the nicotinamide nucleobase. It acts as a reducing agent because
it is able to donate electrons in the form of a hydride. Shown below is the overall synthetic
scheme of the oxidation of NADH to NAD*.
_nicotinamide
adenine nucleobase
H
3
O
NAD+
NH₂
Explain why the oxidation of NADH to NAD* is a favorable reaction even though NAD* gains a
charge?
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