5. Maximize z = 3x, + x2 + 4x3 subject to 3x, + 3x2 + xz < 18 2x1 + 2x2 + 4xz = 12 %3D X1 2 0, x3 2 0. 6. Minimize z = 5x, + 2x2 + 6x3 subject to 4x, + 2x, + X3 z 12 3x, + 2x2 + 3x356 X1 2 0, x2 2 0.
5. Maximize z = 3x, + x2 + 4x3 subject to 3x, + 3x2 + xz < 18 2x1 + 2x2 + 4xz = 12 %3D X1 2 0, x3 2 0. 6. Minimize z = 5x, + 2x2 + 6x3 subject to 4x, + 2x, + X3 z 12 3x, + 2x2 + 3x356 X1 2 0, x2 2 0.
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.6: Multiplying Polynomials
Problem 47WE
Related questions
Question
find the dual of the given linear programming problem
![5. Maximize
subject to
3x1 + x2 + 4x3
z =
3x1 + 3x, + X3 < 18
2x1 + 2x2 + 4xz = 12
x1 2 0, x3 2 0.
6. Minimize
z = 5x1 + 2x2 + 6x3
subject to
4x1 + 2x, + x3 z 12
Зx, + 2х, + 3x, s 6
х, 2 0, х, 2 0.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe89ea604-53d7-4bc6-9cd6-6f45dc437001%2Fb62cbdf5-1b3e-4cc6-9fa0-eebe45f9d00e%2Fne7kte_processed.png&w=3840&q=75)
Transcribed Image Text:5. Maximize
subject to
3x1 + x2 + 4x3
z =
3x1 + 3x, + X3 < 18
2x1 + 2x2 + 4xz = 12
x1 2 0, x3 2 0.
6. Minimize
z = 5x1 + 2x2 + 6x3
subject to
4x1 + 2x, + x3 z 12
Зx, + 2х, + 3x, s 6
х, 2 0, х, 2 0.
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