5. Lars Is standing near the edge of a 90-meter cliff. He throws a ball upward, but does not catch It, and it falls to the bottom of the cliff face. From when he threw the ball upward to when ithit the ground below, 5.55 seconds passed. What was the Initial vertical velocity of Lars' throw?O-11 m/sO 43 m/sO -43 m/sO 11 m/sPREVIOUS5 of 10 NEXTREVIEWSAVE & EXIT<-->CeDIIesc%&backspa

Given data The height of the cliff is given as s = 90 m. The tie interval is given as t = 5.55 s.…

Answered: 5. Lars Is standing near the edge of a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Butch and Sundance are standing on the edge of a cliff, arguing about whether ornot they should jump into the water below. Butch drops a small rock and is able to count to 7-Mississippi (i.e., 7 seconds) before it hits the water. Assume g=10 m/s2.Ignore air resistance.a) If they were to jump, how fast would they be going just before they hit the water?(in m/s)b) How high is the cliff in meters?c) Transform the velocity in a) to mi/hr and the height in b) to feet. Would you jump?
A small rock is thrown vertically upward with a speed of 29.0 m/s from the edge of the roof of a 21.0-m-tall building. The rock doesn't hit the building on its way back down and lands in the street below. Ignore air resistance. Q: How much time elapses from when the rock is thrown until it hits the street? PS: Since someone keeps erasing what comes after Q and stating that the question is incomplete, I have attached an image proving the the entire question has been typed.
The position of a particle moving along the x axis is given by x= (21 + 22t - 5.0t?)m , where tis in s. What is the average velocity during the time interval t= 1.0 s to t=3.0 s? O a. 14 m/s О b. 10 m/s О с. 2 m/s O d. 18 m/s O e. 6 m/s
3. In Physics, the height of a free-falling object at a given time t is given by h = –16t² + v,t + h., where v, is the initial velocity, and h, is the initial height. A student throws a ball upward from a height of 48ft, initially at 32 ft/s. What is the maximum height of the ball?
7. The height of a helicopter above the ground is given by h =20.0 t-5.0 t where h is in meters and t is in seconds. At t=1.00 s, the helicopter releases a small mailbag. a) What is speed of a mailbox before hint to the ground? b) How long mailbox in air? 8. Starting from rest at 5 m from origin, a small still ball's horizontal component of velocity is 90.0 mile/hour in a straight line in 10.0 s. Ball's acceleration is constant during the entire motion, what is ball's final position?
The position of an object as a function of time is given as x = At3 + Bt2 + Ct + D . The constants are A = 2.41 m/s3 B = 1.37 m/s2 ' , C = -4.61 m/s, and D = 3.35 m. What is the velocity of the object at t = 19.10 s? m/s
4. Marcus throws a rock straight up into the air. It leaves his hand 1.2 meters above the ground, and it hits the ground 3.5 seconds later. Find a. the initial speed of the rock when it leaves his hand b. the maximum height the rock reaches before falling back down, relative to the ground c. the speed of the rock right before it hits the ground
9: An archer fires an arrow straight up into the air with a speed v0=35.6m/s. Neglect air resistance. a. Find the maximum height, hℎ, in meters, reached by the arrow. b. In terms of known quantities, write an expression for the time the arrow is in the air until it returns to launch height.
fast plz
6. An object is thrown vertically upward with a speed of 12 m/s. How much time passes before it reaches a speed of 25 m/s downwards? (Air resistance is negligible.) а. 1.3 s b. 1.9 s d. 4.3 s e. 0.80 s с. 3.8 s
An object is thrown straight up in the air with initial speed 20. 0 m/s.What are the velocity and acceleration of the object at its maximum height? Positive y points upward. Ov = 0 m/s, a = 9.81 m/s? Ov%3D -20.0 т/s, a — — 9.81 m/s* v = 20. 0 m/s, a = - 9. 81 m/s? Ov = 0 m/s, a = -9. 81 m/s² Ov= Оv%3D 20.0 m/s, a — 9. 81 m/s? Ov = -20.0 m/s, a = 9. 81 m/s²
The Hint The position of a particle moving along the x axis is given by x = (21 +22t+8t²) m, where t is in s. What is the instantaneous velocity of the particle at t= 5.0 s ? a. b. C. e. f. 10.2m/s -2.0 m/s -82.0m/s 331 m/s 102m/s -6.0 m/s

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