5. Instead of redrawing the molecule to make the lowest priority group point back, alternatively, the lowest priority group can be swapped with the group that is currently pointing back. This is now the enantiomer of the original compound. The procedure is described below. i. Determine priorities of the groups attached to the stereocenter. ii. Swap the lowest priority group with the group that is pointing back, and redraw (this is the enantiomer). iii. Determine the absolute configuration (R or S) of the enantiomer. iv. Determine the absolute configuration (R or S) of the original compound. Answer the following questions. Completely fill in the circle in front of your chosen answer. (a) Assign priorities of the groups at this stereocenter (1 = highest priority; 2 = second priority; 3= third priority; 4 = lowest priority). Each group must have a different priority: CH3 Br H3CH₂C H CH3 O 1 O 2 O 3 04 Br O 1 O 2 O 3 4 (b) The absolute configuration of this compound is: OR OS H O 1 O 2 O 3 O t CH₂CH3 O 1 O 2 O 3 O 4

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5. Instead of redrawing the molecule to make the lowest priority group point back, alternatively, the lowest priority group can be swapped with the group that is currently pointing back. This is now the enantiomer of the original compound. The procedure is described below.
   i. Determine priorities of the groups attached to the stereocenter.
   ii. Swap the lowest priority group with the group that is pointing back, and redraw (this is the enantiomer).
   iii. Determine the absolute configuration (R or S) of the enantiomer.
   iv. Determine the absolute configuration (R or S) of the original compound.

Answer the following questions. Completely fill in the circle in front of your chosen answer.

(a) Assign priorities of the groups at this stereocenter (1 = highest priority; 2 = second priority; 3 = third priority; 4 = lowest priority). Each group must have a different priority:

- CH₃
  - ○ 1
  - ○ 2
  - ○ 3
  - ○ 4

- Br
  - ○ 1
  - ○ 2
  - ○ 3
  - ○ 4

- H
  - ○ 1
  - ○ 2
  - ○ 3
  - ○ 4

- CH₂CH₃
  - ○ 1
  - ○ 2
  - ○ 3
  - ○ 4

(b) The absolute configuration of this compound is:
  
  - ○ R
  - ○ S
Transcribed Image Text:5. Instead of redrawing the molecule to make the lowest priority group point back, alternatively, the lowest priority group can be swapped with the group that is currently pointing back. This is now the enantiomer of the original compound. The procedure is described below. i. Determine priorities of the groups attached to the stereocenter. ii. Swap the lowest priority group with the group that is pointing back, and redraw (this is the enantiomer). iii. Determine the absolute configuration (R or S) of the enantiomer. iv. Determine the absolute configuration (R or S) of the original compound. Answer the following questions. Completely fill in the circle in front of your chosen answer. (a) Assign priorities of the groups at this stereocenter (1 = highest priority; 2 = second priority; 3 = third priority; 4 = lowest priority). Each group must have a different priority: - CH₃ - ○ 1 - ○ 2 - ○ 3 - ○ 4 - Br - ○ 1 - ○ 2 - ○ 3 - ○ 4 - H - ○ 1 - ○ 2 - ○ 3 - ○ 4 - CH₂CH₃ - ○ 1 - ○ 2 - ○ 3 - ○ 4 (b) The absolute configuration of this compound is: - ○ R - ○ S
Expert Solution
Step 1: The rules to identify the absolute configuration

The important rules for assigning the absolute configuration of a chiral center according to CIP rules are as follows:

The carbon which is attached with four different groups is called a chiral center (or) stereogenic center.

The arrangement of groups based on priority around the chiral center gets R or S configuration.

When the least priority group on dash line and highest priority group on wedge line ( thick line ) or in plane the clockwise arrangement gets R configuration and the anti-clockwise arrangement gets S configuration.

When the least priority group on wedge line ( thick line ) and highest priority group on dash line the clockwise arrangement gets S configuration and the anti-clockwise arrangement gets R configuration.

The priority given to the groups based on atomic number or atomic mass of an atom which is directly attached to the chiral center. More atomic numbers get highest priority. If chiral center attached with same atoms then is go for the next atom for comparison.


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