5. In another titration, a student uses 1.023 M HCl solution to standardize a sodium hydroxide solution. Perform the following calculations, assuming there is 1.000 L of HCl solution, and its density is 1.019 g/mL. Show all of your work on this page or on a separate sheet of paper. a. Beginning with the molarity of HCl, calculate the mass percent of HCl in the HCl solution. This calculation should be done all in one string. You should use the density of the solution and the molar mass of HCl in your calculation string. Record your answer to the appropriate number of sf. Mass percent: b. Use the following process to calculate the molality of HCl in the solution. This calculation should be performed in multiple steps, illustrated below. i. Beginning with the volume of HCl solution (1.000 L HC1), determine the grams of total solution. You will need the density of HCl to calculate this. Track the sf in your work below. Example: 2039,56 g solution ii. Beginning with the volume of HCl solution, use the molarity and the molar mass of HCl to determine the mass of HCl (solute). Track the sf in your work below. Example: 12.2256 g iii. Use the unrounded and tracked values from parts į and ii to determine the mass of solvent in grams. Pay close attention to the sig figs for the subtraction! Track the sf in your work below. Example: 335.678 g/ iv. Beginning with the volume of HCl solution, use the molarity and the unrounded and tracked mass of solvent from iii (converted to kg) to determine the molality. This calculation should be done all in one string (including the conversion to kg.)
5. In another titration, a student uses 1.023 M HCl solution to standardize a sodium hydroxide solution. Perform the following calculations, assuming there is 1.000 L of HCl solution, and its density is 1.019 g/mL. Show all of your work on this page or on a separate sheet of paper. a. Beginning with the molarity of HCl, calculate the mass percent of HCl in the HCl solution. This calculation should be done all in one string. You should use the density of the solution and the molar mass of HCl in your calculation string. Record your answer to the appropriate number of sf. Mass percent: b. Use the following process to calculate the molality of HCl in the solution. This calculation should be performed in multiple steps, illustrated below. i. Beginning with the volume of HCl solution (1.000 L HC1), determine the grams of total solution. You will need the density of HCl to calculate this. Track the sf in your work below. Example: 2039,56 g solution ii. Beginning with the volume of HCl solution, use the molarity and the molar mass of HCl to determine the mass of HCl (solute). Track the sf in your work below. Example: 12.2256 g iii. Use the unrounded and tracked values from parts į and ii to determine the mass of solvent in grams. Pay close attention to the sig figs for the subtraction! Track the sf in your work below. Example: 335.678 g/ iv. Beginning with the volume of HCl solution, use the molarity and the unrounded and tracked mass of solvent from iii (converted to kg) to determine the molality. This calculation should be done all in one string (including the conversion to kg.)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1
a) Mass percent = ?
Moles of HCl are,
Moles = molarity × volume
Moles = 1.023 M × 1.0 L
Moles = 1.023 mol
Now the mass of HCl is,
Moles = mass ÷ molar mass
Mass = moles × molar mass
Mass = 1.023 mol × 36.458 g/mol
Mass = 37.30 g
Now, the mass of 1.0 L HCl solution is,
Mass = density × volume
Mass = 1.019 g/mL × 1000 mL
Mass = 1019 g
Now, the mass percent of HCl in HCl solution is,
Mass percent = (mass of solute ÷ mass of solution) × 100%
Mass percent = (37.30 g ÷ 1019 g) × 100%
Mass percent = 3.66%
Therefore, the mass percent of HCl in the HCl solution is 3.66%.
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