if the marble is launched with the launch speed V_{o} but at an initial angle of , what would be the expression of v_{0} in terms of horizontal displacement x and vertical displacement y? Hint: y = (v_{0} * sin theta) * t - 1/2 * q * t ^ 2 and replace t using x = (v_{0} * cos theta) t . (See Instructions)Height of the table (top surface) y = 0.76 m.Get the data for the "t" and "x" columns and proceed toanalysis (below the table) to fill in the rest of the table.Trial1Trial2Trial3Trial4Trial50.4460.4100.4210.3990.431t0.5080.7110.8630.5580.838X1.1391.7342.0491.3981.94401.20 1.25 1.30 1.35 1.40 1.45 1.50 1.55 1.60 1.65 1.70Time (s)Vo (usingx/t)1.291.82.191.462.127Vo (using√(gx²/2y)) 5. If the marble is launched with the launch speed vo but at aninitial angle of 0, what would be the expression of v, in termsof horizontal displacement x and vertical displacement y?Hint: y = (vo sine) t - ½ gt² and replace t using x = (v₁ cose) t.

Initial speed of a projectile is .The launch angle is .Note:Find:Expression for initial speed in…

Answered: 5. If the marble is launched with the…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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if the marble is launched with the launch speed V_{o} but at an initial angle of , what would be the expression of v_{0} in terms of horizontal displacement x and vertical displacement y? Hint: y = (v_{0} * sin theta) * t - 1/2 * q * t ^ 2 and replace t using x = (v_{0} * cos theta) t .

(See Instructions)
Height of the table (top surface) y = 0.76 m.
Get the data for the "t" and "x" columns and proceed to
analysis (below the table) to fill in the rest of the table.
Trial
1
Trial
2
Trial
3
Trial
4
Trial
5
0.446
0.410
0.421
0.399
0.431
t
0.508
0.711
0.863
0.558
0.838
X
1.139
1.734
2.049
1.398
1.944
0
1.20 1.25 1.30 1.35 1.40 1.45 1.50 1.55 1.60 1.65 1.70
Time (s)
Vo (using
x/t)
1.29
1.8
2.19
1.46
2.127
Vo (using
√(gx²/2y))

5. If the marble is launched with the launch speed vo but at an
initial angle of 0, what would be the expression of v, in terms
of horizontal displacement x and vertical displacement y?
Hint: y = (vo sine) t - ½ gt² and replace t using x = (v₁ cose) t.

Expert Solution

Step 1: Given data

Initial speed of a projectile is $v subscript 0$ .

The launch angle is $theta$ .

Note:

$fraction numerator sin open parentheses x close parentheses over denominator cos open parentheses x close parentheses end fraction equals tan open parentheses x close parentheses$

Find:

Expression for initial speed $v subscript 0$ in terms of horizontal and vertical displacement.

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