5. h After: 30⁰ Before: 2 2 m₁ = 2 kg m₂ = 3kg h = 50 cm Mass 1 is released from rest from height hand slides down a frictionless 30° slope then collides with mass 2. The two masses then stick together and move as a unit on the horizontal ground. a. What is the speed of mass 1 at the bottom of the slope just before it hits mass 2? b. Mass 2 is initially at rest at the bottom of the slope. Mass 1 now collides with mass 2. Find the speed of the combined masses after the collision. c. How much energy was lost in this collision?
5. h After: 30⁰ Before: 2 2 m₁ = 2 kg m₂ = 3kg h = 50 cm Mass 1 is released from rest from height hand slides down a frictionless 30° slope then collides with mass 2. The two masses then stick together and move as a unit on the horizontal ground. a. What is the speed of mass 1 at the bottom of the slope just before it hits mass 2? b. Mass 2 is initially at rest at the bottom of the slope. Mass 1 now collides with mass 2. Find the speed of the combined masses after the collision. c. How much energy was lost in this collision?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:5.
After:
30⁰
Before:
2
1
2
V'
m₁ = 2 kg m₂ = 3kg
h = 50 cm
Mass 1 is released from rest from height hand
slides down a frictionless 30° slope then collides
with mass 2. The two masses then stick together
and move as a unit on the horizontal ground.
a. What is the speed of mass 1 at the bottom of the slope just before it hits mass 2?
b. Mass 2 is initially at rest at the bottom of the slope. Mass 1 now collides with mass 2. Find
the speed of the combined masses after the collision.
c. How much energy was lost in this collision?
Expert Solution
Step 1
The following problem utilizes the concepts of conservation of energy and the law of conservation of momentum. The potential energy of the block transforms into kinetic energy at the bottom of the slope and collides with the second block.
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