5. Given the following equation: 2 FePO4 + 3 Na2SO4 → Fe2(SO4)3+2 Na3PO4 If I perform this reaction with 25 g of Iron (III) phosphate (FePO4) and 33 g of sodium sulfate(Na₂SO4), what is the limiting and excess reactant and how much sodium phosphate (Na₂PO4) will be formed? Limiting Reactant: Excess Reactant: Part 1: 25g FePO4 Step 1: mass to moles Molar mass of FePO4 =150.12 g/mol moles FePO4 25g FePO4 + molar mass of FePO4 = the balanced equation

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5. Given the following equation: 2 FePO4+3 Na2SO4 → Fe2(SO4)3+2 Na3PO4
If I perform this reaction with 25 g of Iron (III) phosphate (FePO4) and 33 g of sodium
sulfate(Na₂SO4), what is the limiting and excess reactant and how much sodium phosphate (Na₂PO4)
will be formed?
Limiting Reactant:
Excess Reactant:
Part 1: 25g FePO4
Step 1: mass to moles
Molar mass of FePO4 =150.12
g/mol
moles FePO4
25g FePO4 + molar mass of FePO4 =
the balanced equation
Transcribed Image Text:5. Given the following equation: 2 FePO4+3 Na2SO4 → Fe2(SO4)3+2 Na3PO4 If I perform this reaction with 25 g of Iron (III) phosphate (FePO4) and 33 g of sodium sulfate(Na₂SO4), what is the limiting and excess reactant and how much sodium phosphate (Na₂PO4) will be formed? Limiting Reactant: Excess Reactant: Part 1: 25g FePO4 Step 1: mass to moles Molar mass of FePO4 =150.12 g/mol moles FePO4 25g FePO4 + molar mass of FePO4 = the balanced equation
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