5. Given that f: [0, 1] →R satisfies If(z) - f(u)| < |x - yl for all r, y € (0, 1] with z#y. Can We conclude that there exists a constant K <1 such that for all z,y € (0, 1] IS(2) - f(y) S Kz- yl? Hint: consider f(r) = sin r.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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4. Suppose that f,9: [0, 1] - (0, ox] are continuous functions and that
sup{f(x) : E (0, 1]} = sup{g(r): r€ [0,1]}.
Prove that there exists t € (0, 1] such that f(t) = g(t).
5. Given that f: [0, 1] - R satisfies
If(r) – f(y)| < |x - yl
for all r, y e [0, 1] with z # y. Can We conclude that there exists a constant K <1 such that for all
a, y € [0, 1]
If(2) – f(y)| < K|a - y?
Hint: consider f(r) = sin r.
Transcribed Image Text:4. Suppose that f,9: [0, 1] - (0, ox] are continuous functions and that sup{f(x) : E (0, 1]} = sup{g(r): r€ [0,1]}. Prove that there exists t € (0, 1] such that f(t) = g(t). 5. Given that f: [0, 1] - R satisfies If(r) – f(y)| < |x - yl for all r, y e [0, 1] with z # y. Can We conclude that there exists a constant K <1 such that for all a, y € [0, 1] If(2) – f(y)| < K|a - y? Hint: consider f(r) = sin r.
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