3. Find and sketch the domains of f(x, y) = xy and g(x, y) = xy In(9-x² - 9y²)*

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem 38

#### Task:
Find and sketch the domains of the following functions:

\[ f(x, y) = \frac{e^{-y}}{\sqrt{xy}} \]
\[ g(x, y) = \frac{xy}{\ln(9 - x^2 - 9y^2)} \]

#### Steps to Determine the Domains:

##### For \( f(x, y) = \frac{e^{-y}}{\sqrt{xy}} \):
1. **Identify the restrictions on \(x\) and \(y\)**:
   - The denominator \(\sqrt{xy}\) must be positive since you cannot take the square root of a negative number or zero.
   - Therefore, \( x > 0 \) and \( y > 0 \).
   
2. **Express the Conditions**:
   - The domain of \( f(x, y) \) is given by the set:
   \[
   D_f = \{ (x, y) \in \mathbb{R}^2 \mid x > 0, y > 0 \}
   \]

##### For \( g(x, y) = \frac{xy}{\ln(9 - x^2 - 9y^2)} \):
1. **Identify the restrictions on \(x\) and \(y\)**:
   - The argument of the logarithmic function \(\ln(9 - x^2 - 9y^2)\) must be positive: \( 9 - x^2 - 9y^2 > 0 \).
   - Therefore, \( x^2 + 9y^2 < 9 \):
     - This inequality describes an ellipse centered at the origin with semi-major axis 3 (along the x-axis) and semi-minor axis 1 (along the y-axis).
   - The logarithmic function \(\ln(9 - x^2 - 9y^2)\) must not equal zero, which implies \( 9 - x^2 - 9y^2 \neq 1 \).
   
2. **Express the Conditions**:
   - The domain of \( g(x, y) \) is given by the set:
   \[
   D_g = \left\{ (x, y) \in \mathbb{R}^2 \mid x^2 + 9y^2 < 9 \text
Transcribed Image Text:### Problem 38 #### Task: Find and sketch the domains of the following functions: \[ f(x, y) = \frac{e^{-y}}{\sqrt{xy}} \] \[ g(x, y) = \frac{xy}{\ln(9 - x^2 - 9y^2)} \] #### Steps to Determine the Domains: ##### For \( f(x, y) = \frac{e^{-y}}{\sqrt{xy}} \): 1. **Identify the restrictions on \(x\) and \(y\)**: - The denominator \(\sqrt{xy}\) must be positive since you cannot take the square root of a negative number or zero. - Therefore, \( x > 0 \) and \( y > 0 \). 2. **Express the Conditions**: - The domain of \( f(x, y) \) is given by the set: \[ D_f = \{ (x, y) \in \mathbb{R}^2 \mid x > 0, y > 0 \} \] ##### For \( g(x, y) = \frac{xy}{\ln(9 - x^2 - 9y^2)} \): 1. **Identify the restrictions on \(x\) and \(y\)**: - The argument of the logarithmic function \(\ln(9 - x^2 - 9y^2)\) must be positive: \( 9 - x^2 - 9y^2 > 0 \). - Therefore, \( x^2 + 9y^2 < 9 \): - This inequality describes an ellipse centered at the origin with semi-major axis 3 (along the x-axis) and semi-minor axis 1 (along the y-axis). - The logarithmic function \(\ln(9 - x^2 - 9y^2)\) must not equal zero, which implies \( 9 - x^2 - 9y^2 \neq 1 \). 2. **Express the Conditions**: - The domain of \( g(x, y) \) is given by the set: \[ D_g = \left\{ (x, y) \in \mathbb{R}^2 \mid x^2 + 9y^2 < 9 \text
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