5. From the activation energy (Ea) and collision frequency factor (A) that you determined in this experiment, calculate the rate constant at 85 degrees Celsius.
5. From the activation energy (Ea) and collision frequency factor (A) that you determined in this experiment, calculate the rate constant at 85 degrees Celsius.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The activasion energy is -9.590 KJ/mol
The collision frequency is 7.05x10^8
![**Question 5: Calculation of Rate Constant Using Arrhenius Equation**
From the activation energy (Ea) and collision frequency factor (A) that you determined in this experiment, calculate the rate constant at 85 degrees Celsius.
**Instruction:**
To complete this calculation, use the Arrhenius equation given by:
\[ k = A \cdot e^{-\frac{E_a}{RT}} \]
Where:
- \( k \) is the rate constant.
- \( A \) is the collision frequency factor.
- \( E_a \) is the activation energy.
- \( R \) is the universal gas constant (\( 8.314 \, \text{J/mol·K} \)).
- \( T \) is the temperature in Kelvin.
Here, convert the temperature from Celsius to Kelvin using the formula:
\[ T(K) = T(°C) + 273.15 \]
For 85 degrees Celsius:
\[ T = 85 + 273.15 = 358.15 \, \text{K} \]
Substitute the values of \( A \), \( E_a \), \( R \), and \(T \) into the Arrhenius equation to determine the rate constant \( k \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa755e52e-afcf-45db-bf55-07fc4c384d8b%2F760c1a88-09d5-48d2-a4c1-36b62765f349%2Flutxcj5_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 5: Calculation of Rate Constant Using Arrhenius Equation**
From the activation energy (Ea) and collision frequency factor (A) that you determined in this experiment, calculate the rate constant at 85 degrees Celsius.
**Instruction:**
To complete this calculation, use the Arrhenius equation given by:
\[ k = A \cdot e^{-\frac{E_a}{RT}} \]
Where:
- \( k \) is the rate constant.
- \( A \) is the collision frequency factor.
- \( E_a \) is the activation energy.
- \( R \) is the universal gas constant (\( 8.314 \, \text{J/mol·K} \)).
- \( T \) is the temperature in Kelvin.
Here, convert the temperature from Celsius to Kelvin using the formula:
\[ T(K) = T(°C) + 273.15 \]
For 85 degrees Celsius:
\[ T = 85 + 273.15 = 358.15 \, \text{K} \]
Substitute the values of \( A \), \( E_a \), \( R \), and \(T \) into the Arrhenius equation to determine the rate constant \( k \).
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