5. Forces of 16N and 12N are acting on a mass of 200kg in mutually perpendicular directions. Find the magnitude of the acceleration produced?
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A: Given data: F =(6i-2j) N d =(2i+3j) m Required: The angle between F and d
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A: Total moment around O is Moment=(10*2)+(5*4)+(5*7)=20+20+35=75 Nm
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Q: the magnitude of the acceleration produced?
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Q: 21 - A force of F =(6i-2j) N acts on a particle, displacing it by d =(2i+3j) m. Find the angle…
A: Given : F =(6i-2j) N d =(2i+3j) m
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