5. For the function f: RR by f(x)=x²-3x = x(x-3), you can tell by inspection that its roots are * = 0 and 2* = 3. Nevertheless, we'll use Newton's Algorithm to approximately find at least one of them! So that you can focus on the algorithm and NOT on how to numerically compute derivatives, you are given that df (x) dx (a) For xo = 1, complete the following Table using Newton's Algorithm. You do not need to show your work. k Xk f(xk) 23 0 1.00 -2.00 -1.00 1 k =2x-3. (b) For o 2, complete the following Table using Newton's Algorithm. You do not need to show your work. ایران 0 2.00 -2.00 1 2 3 df (xk) dx Xk f(xk) df(xk) dx 1.00
5. For the function f: RR by f(x)=x²-3x = x(x-3), you can tell by inspection that its roots are * = 0 and 2* = 3. Nevertheless, we'll use Newton's Algorithm to approximately find at least one of them! So that you can focus on the algorithm and NOT on how to numerically compute derivatives, you are given that df (x) dx (a) For xo = 1, complete the following Table using Newton's Algorithm. You do not need to show your work. k Xk f(xk) 23 0 1.00 -2.00 -1.00 1 k =2x-3. (b) For o 2, complete the following Table using Newton's Algorithm. You do not need to show your work. ایران 0 2.00 -2.00 1 2 3 df (xk) dx Xk f(xk) df(xk) dx 1.00
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:5. For the function f : R → R by f(x) = x²-3x = x(x - 3), you can tell by inspection that its roots are x* = 0 and x* = 3.
Nevertheless, we'll use Newton's Algorithm to approximately find at least one of them!
So that you can focus on the algorithm and NOT on how to numerically compute derivatives, you are given that
df (x)
dx
(a) For xo = 1, complete the following Table using Newton's Algorithm. You do not need to show your work.
k
= 2x - 3.
Xk f(xk)
k
0 1.00 -2.00 -1.00
1
2
3
(b) For xo = 2, complete the following Table using Newton's Algorithm. You do not need to show your work.
df (xk)
dx
df (xk)
dx
Xk f(xk)
0 2.00 -2.00
1
2
3
1.00
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