5. Find the current in the R1 resistor in the drawing (V1 = 16.0 V, V2 = 18.0 V, V3 = 15.0 V, R1 = 2.00 2, R2 = 2.00 S2, and R3 = 2.30 2). ww- R, R, R3 V, def19 oof19 o 19 0of19 oof19

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Chapter1: Units, Trigonometry. And Vectors
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5. Find the current in the R, resistor in the drawing (V1 = 16.0 V, V2 = 18.0 V, V3 = 15.0 V, R1 = 2.00 2, R2 = 2.00 2, and R3 =
2.30 N).
oof19 0of
ww
R,
R2
of19 oof19 oof19 oo
oof19 0of19 oof19 oot
oof19 0of19
Transcribed Image Text:5. Find the current in the R, resistor in the drawing (V1 = 16.0 V, V2 = 18.0 V, V3 = 15.0 V, R1 = 2.00 2, R2 = 2.00 2, and R3 = 2.30 N). oof19 0of ww R, R2 of19 oof19 oof19 oo oof19 0of19 oof19 oot oof19 0of19
Expert Solution
Step 1

Kirchhoff’s second rule is an application of conservation of energy. It is also  known as the loop rule.

Apply Kirchoff's second rule to loop 1

Physics homework question answer, step 1, image 1

V1- I1R1-I2R3+V3=0

16-2I1-2.3I2+15=0

31-2I1-2.3I2=0                          .....(1)

Apply Kirchoff's rule 2 to loop 2

Physics homework question answer, step 1, image 2

V3+V2+( I1-I2 )R2- I2 R3=0

15+18+2I1-2I2 -2.3I2 =0

33+2I1-4.3I2=0                     ......(2)

Adding eqns 1 and 2 one will get

64-6.6I2=0

I2=9.69 A

Put this value of I2 in eq.2

I1=3.8 A

 

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