5. Determine the location and value of the absolute extreme values of f on the given interval, if they exist. F(1) == 16 f(x) = ¹ + x², (1,4). Т 17 16 +1² F(x) = 16 +2+ 16 + 2(1) - 18

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem 5: Extreme Value Theorem**

Determine the location and value of the absolute extreme values of \( f \) on the given interval, if they exist.

\[ f(x) = \frac{16}{x} + x^2 \]
Interval: \([1, 4]\)

**Solution Steps:**

1. Calculate \( f(1) \):
   \[
   f(1) = \frac{16}{1} + 1^2 = 16 + 1 = 17
   \]

2. Check critical points and endpoints to determine absolute extreme values.

There is a possibility of further calculation beyond what is provided, such as taking the derivative, setting it to zero, and solving for \( x \) to find critical points. This helps in confirming whether the extreme values occur at endpoints or critical points within the interval.
Transcribed Image Text:**Problem 5: Extreme Value Theorem** Determine the location and value of the absolute extreme values of \( f \) on the given interval, if they exist. \[ f(x) = \frac{16}{x} + x^2 \] Interval: \([1, 4]\) **Solution Steps:** 1. Calculate \( f(1) \): \[ f(1) = \frac{16}{1} + 1^2 = 16 + 1 = 17 \] 2. Check critical points and endpoints to determine absolute extreme values. There is a possibility of further calculation beyond what is provided, such as taking the derivative, setting it to zero, and solving for \( x \) to find critical points. This helps in confirming whether the extreme values occur at endpoints or critical points within the interval.
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