5. Determine the amount of shearing stress develop in a material when a force of 60N is applied to a piece of working materials having a cross sectional area of 5 m??
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A: Given : Area of cross section , A = 8 mm2 = 8× 10-6 m2 Force = 1600 N
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A: Out of the four quantities which is the material constant.
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Q: "There are 3 main types of stress .....
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Q: fe magnitude of the load w?
A: Given as, l=8 m. Load at 1 kN from support= 5 kN. Horizontal shearing stress= 80 MPa.
Q: What force is required to punch a 30 strength is 310 MN/m??
A: GivenDiameter of hole, d=30.115 mmThickness pf plate, t=15 mmShear strength , τ=310 MN/m2
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