5. Calçulate the expected value of the game E = PAQ if %3D - %3D P [2 .8] %3D and Q = %3D
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![5. Calçulate the expected value of the game E = PAQ if
%3D
A =
2 -1
P = [.2 .8]
and
.31
%3D
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- A medical researcher says that less than 82% of adults in a certain country think that healthy children should be required to be vaccinated. In a randon sample of 300 adults in that country, 78% think that healthy children should be required to be vaccinated. At a = 0.10, is there enough evidence to support the researcher's claim? Complete parts (a) through (e) below. (a) Identify the claim and state Ho and Ha Identify the claim in this scenario. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) CA. Less than 82 % of adults in the country think that healthy children should be required to be vaccinated. O B. The percentage of adults in the country who think that healthy children should be required to be vaccinated is not %. O C. More than % of adults in the country think that healthy children should be required to be vaccinated. O D. % of adults in the country think that healthy children should be required…In a random sample of 1022 Canadian adults, 480 think that the Canadian government is doing too little to protect the environment. In another random sample of 1008 Canadian adults taken 10 years ago, 514 think that the Canadian government is doing too little to protect the environment. At a=0.10, can you reject the claim that the proportion of US adults who think that the Canadian government is doing too little to protect the environment hasn't changed?Researchers suspect that 18% of all high school students smoke at least one pack of cigarettes a day. At Wilson High School, with an enrolment of 300 students, a study found that 50 students smoked at least one pack of cigarettes a day. At a = 0.04, test the claim that 18% of all high school students smoke at least one pack of cigarettes a day.
- What is E(T) where is a T random variable with 17 degrees of freedom?The manager of the city pool has scheduled extra lifeguards to be on staff for Saturdays. However, he suspects that Fridays may be more popular than the other weekdays as well. If so, he will hire extra lifeguards for Fridays, too. In order to test his theory that the daily number of swimmers varies on weekdays, he records the number of swimmers each day for the first week of summer. Test the manager’s theory at the 0.01 level of significance. Swimmers at the City Pool Monday Tuesday Wednesday Thursday Friday Number 64 46 41 56 70 Copy Data Step 2 of 4 : Calculate the expected value for the number of swimmers on Tuesday. Enter your answer as a fraction or a decimal rounded to three decimal places.Suppose the lifespan (in months) of a smartphone battery can be modeled as a continuous random variable with CDF F(x) = 1 − e-x/3 x ≥ 0 What is the probability that the battery lasts between 12 to 15 months?
- A family purchases a 2000 square foot home and plans to make extensions totalling 500 square feet. The house currently has a pool, and a real estate agent has reported that the house is in excellent condition. However, the house does not have a view, and this will not change as a result of the extensions. According to the results in column (1), what is the expected DOLLAR increase in the price of the home due to the planned extensions?NEED NEED ANSWER ASAP !!!Let T : R* → R? be the linear transformation where N(T) = span{(1,0,0, 0), (0, 1, 0, 0)}. Is T one-to-one? Is T onto?
- A research center claims that 31% of adults in a certain country would travel into space on a commercial flight if they could afford it. In a random sample of 800 adults in that country, 33% say that they would travel into space on a commercial flight if they could afford it. At a =0.01, is there enough evidence to reject the research center's claim? Complete parts (a) through (d) below. C No more than % of adults in the country would travel into space on a commercial ight it they could attord it. Let p be the population proportion of successes, where a success is an adult in the country who would travel into space on a commercial flight if they could afford it. State Ho and H Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.) OA Ho: ps OB. Ho: p> OC. Ho: p H p= Ha:p> H ps VE Ho: p= 0.31 O D. Ho: p< OF H: p2 H: p2 H p 0.31 (b) Use technology to find the P-value. Identify the standardized test statistic. z= 1.22…A research center claims that 31% of adults in a certain country would travel into space on a commercial flight if they could afford it. In a random sample of 1200 adults in that country, 33% say that they would travel into space on a commercial flight if they could afford it. At a = 0.05, is there enough evidence to reject the research center's claim? Complete parts (a) through (d) below. %3D Ta·マー TaPー D. Ho pS E. Ho: p2 O F. Ho:p# Haip> Ha:p< Haip= W (b) Use technology to find the P-value. Identify the standardized test statistic. Z= (Round to two decimal places as needed.) Enter your answer in the answer box and then click Check Answer. ?Benford's Law claims that numbers chosen from very large data files tend to have "1" as the first nonzero digit disproportionately often. In fact, research has shown that if you randomly draw a number from a very large data file, the probability of getting a number with "1" as the leading digit is about 0.301. Suppose you are an auditor for a very large corporation. The revenue report involves millions of numbers in a large computer file. Let us say you took a random sample of n = 250 numerical entries from the file and r = 60 of the entries had a first nonzero digit of 1. Let p represent the population proportion of all numbers in the corporate file that have a first nonzero digit of 1. Test the claim that p is less than 0.301 by using α = 0.01. What does the area of the sampling distribution corresponding to your P-value look like? a. The area in the right tail of the standard normal curve. b. The area not including the right tail of the standard normal curve.…
