5. C7H100%T100806040HR200500646NS20T9T82.0001:T73000ell1: 1T T6T5:ppm2000T4ele32T2:3multiplet15001Wavenumber[cm-1]marginal01000500 400180 160 140CR200500646NSallDEPT-90135DEPT-1354120100ppmسل806040200

The question is based on the concept of organic spectroscopy. We need to analyse the spectral data and identify the compound.First, we calculated the degree of unsaturation which was found to be 3.We analysed the IR spectra and found that it is an aromatic hydrocarbon.Next , we assign fragments to different delta values and subsequent joining the fragments we obtain the compound.Finally, we assign carbon to different delta values using C NMR spectra data.CONCLUSION;HENCE, the compound was found to be3-Propyl furan

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Chemistry

5. C7H100 %T 9 HR200500646NS 100 80 60 40 20 2000 8 1 1:1 7 لار 3000 6 5 : ppm 2000 4 Waussu بلد 3 like 22:3 1500 11 1 multiplet 0 1000 500 400 180 160 140 CR2005006-45NS öll DEPT-90 1354 DEPT-135A 120 100 ppm T 80 T 60 T 40 20 0

5. C7H100 %T 9 HR200500646NS 100 80 60 40 20 2000 8 1 1:1 7 لار 3000 6 5 : ppm 2000 4 Waussu بلد 3 like 22:3 1500 11 1 multiplet 0 1000 500 400 180 160 140 CR2005006-45NS öll DEPT-90 1354 DEPT-135A 120 100 ppm T 80 T 60 T 40 20 0

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A class of chemistry students measured the density of an unknown liquid. If the correct density of the sample is 1.14 g/mL, what is the percent error for their average experimental density? Group Density (g/mL) 1 1.033 1.185 1.075 4 1.026 1.135 1.022 %E = 94.6% %3D %E = 5.4% %3D %E = 6.1% %E = 5.7%
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STARTING AMOUNT X A particular beer is 6.50 % ethanol by volume (C₂H₂O). If a single bottle of beer contains 750.0 mL of beer, what mass, in g of ethanol (C₂H₂O), is present in the bottle? The density of ethanol is 0.789 g ethanol/mL ethanol 3.85 6.18 ADD FACTOR x( ) 61.8 0.385 6.50 Question 16 of 24 0.001 9.10 × 104 38.5 10 ANSWER 0.01 1 %v ethanol mL ethanol mL ethanol/mL beer 0.789 750.0 g ethanol RESET 3 0.1 100 mL beer 1000 0.618 Submit +
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chips trial mass of the chip mass of the fat %by mass of fat regular 1 20.043 6.745 33.65% 2 20.187 6.438 31.89% 3 20.198 7.451 36.89% lowfat 1 19.456 3.982 20.47% 2 20.072 4.547 22.65% 3 20.192 4.589 22.73% Calculate the average % by mass of fat for each type of chip. Show your work.