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1. Using the slope formula, determine the slope of the line. Slope 45 40 Mass of Solute (g) 35 302 20 15 10 5 05 0 5 10 65329 = 15 25 Volume of Solution (mL) 15.0+ 33.0ML = 56.0 ML 12 Ay = 1₂ - 1₁ ду - Ax Xx2-x, Ay =30(g) — 2119) Ax 29 (ml)-20 (m²) Ay Ах ду Ax 40 35 *30 9 9 2. Using the graph above, what is the mass of solute found in 8.0, 15.0, and 33.0 mL of solution? Mass DXV

1. Using the slope formula, determine the slope of the line. Slope 45 40 Mass of Solute (g) 35 302 20 15 10 5 05 0 5 10 65329 = 15 25 Volume of Solution (mL) 15.0+ 33.0ML = 56.0 ML 12 Ay = 1₂ - 1₁ ду - Ax Xx2-x, Ay =30(g) — 2119) Ax 29 (ml)-20 (m²) Ay Ах ду Ax 40 35 *30 9 9 2. Using the graph above, what is the mass of solute found in 8.0, 15.0, and 33.0 mL of solution? Mass DXV

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer number 2. Thanks

1. Using the slope formula, determine the slope of the line. Slope 45 40 Mass of Solute (g) 35 30 25 20 15 10 Y2 5 Ye 0 0 5 10 X 20 15 25 Volume of Solution (mL) Mass DXV V=8.0+ 15.0+ 33.0 ML = 56.0ML ду Ax JC 230 - 12 =Y₂ - Y₁ x2-x. 1 Ay = 3019) - 2119) Ax 29 (ml)-20 (ml) Ay 7/85/ 35 marbles (g) Ах ду A24 40 9 9 2. Using the graph above, what is the mass of solute found in 8.0, 15.0, and 33.0 mL of solution? = 1
Transcribed Image Text:1. Using the slope formula, determine the slope of the line. Slope 45 40 Mass of Solute (g) 35 30 25 20 15 10 Y2 5 Ye 0 0 5 10 X 20 15 25 Volume of Solution (mL) Mass DXV V=8.0+ 15.0+ 33.0 ML = 56.0ML ду Ax JC 230 - 12 =Y₂ - Y₁ x2-x. 1 Ay = 3019) - 2119) Ax 29 (ml)-20 (ml) Ay 7/85/ 35 marbles (g) Ах ду A24 40 9 9 2. Using the graph above, what is the mass of solute found in 8.0, 15.0, and 33.0 mL of solution? = 1
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