5. Bobby and Jane dissolve 13.4 g of solid potassium iodide in water, then pour the solution into an excess of concentrated lead () nitrate. Jane carefully filters the resulting yellow precipitate from the solution and dries the solid overnight. The following day, Bobby finds the mass of the precipitate (which he knows to be Pbl,) to be 17.4 g. What is the percent yield of Bobby and Jane's reaction? 2KI + Pb(NO3)2→ 2KNO3 + Pbl,

Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
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Chapter11: Stoichiometry
Section: Chapter Questions
Problem 47A: When hydrochloric acid solution reacts with lead (ll) nitrate solution, lead (Il) chloride...
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5. Bobby and Jane dissolve 13.4 g of solid potassium iodide in water, then pour the solution into an
excess of concentrated lead (II) nitrate. Jane carefully filters the resulting yellow precipitáte
from the solution and dries the solid overnight. The following day, Bobby finds the mass of the
precipitate (which he knows to be Pbl,) to be 17.4 g. What is the percent yield of Bobby and
Jane's reaction?
2KI + Pb(NO3)2 → 2KNO3 + Pbl,
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O Type here to search
Transcribed Image Text:5. Bobby and Jane dissolve 13.4 g of solid potassium iodide in water, then pour the solution into an excess of concentrated lead (II) nitrate. Jane carefully filters the resulting yellow precipitáte from the solution and dries the solid overnight. The following day, Bobby finds the mass of the precipitate (which he knows to be Pbl,) to be 17.4 g. What is the percent yield of Bobby and Jane's reaction? 2KI + Pb(NO3)2 → 2KNO3 + Pbl, < PREVIOUS O Type here to search
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