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1. Show your work to solve the following equation: (200 - Vmik) (30 °C) = Vmik (61°C) 2. How much heat is required to heat a 18.4 g ice cube from -23.0 °C to -1.0 °C? Specific heat of ice is 2.108 J/g °C. Show your work.

1. Show your work to solve the following equation: (200 - Vmik) (30 °C) = Vmik (61°C) 2. How much heat is required to heat a 18.4 g ice cube from -23.0 °C to -1.0 °C? Specific heat of ice is 2.108 J/g °C. Show your work.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. Show your work to solve the following equation: (200 - Vmilk) (30 °C) = Vmilk (61°C) 2. How much heat is required to heat a 18.4 g ice cube from -23.0 °C to -1.0 °C? Specific heat of ice is 2.108 J/g °C. Show your work. 3. How much would the temperature of 275 g of water increase if 36.5 kJ of heat were added? Specific heat of water is 4.184 J/g°C. Show your work. 4. A 45-g aluminum spoon (specific heat 0.88 J/g °C) at 24 °C is placed in 180 mL (180 g) of water at 85 °C and the temperature of the two become equal. Specific heat of water is 4.184 J/g °C. What is the final temperature when the two become equal? Show your work.
Transcribed Image Text:1. Show your work to solve the following equation: (200 - Vmilk) (30 °C) = Vmilk (61°C) 2. How much heat is required to heat a 18.4 g ice cube from -23.0 °C to -1.0 °C? Specific heat of ice is 2.108 J/g °C. Show your work. 3. How much would the temperature of 275 g of water increase if 36.5 kJ of heat were added? Specific heat of water is 4.184 J/g°C. Show your work. 4. A 45-g aluminum spoon (specific heat 0.88 J/g °C) at 24 °C is placed in 180 mL (180 g) of water at 85 °C and the temperature of the two become equal. Specific heat of water is 4.184 J/g °C. What is the final temperature when the two become equal? Show your work.
Experimental procedure: 1. Place a bottle of hot coffee, a bottle of milk, and a 0.2L foam cup (in Glassware→Other) on the work bench. The foam cup is thermal insulating so it won't lose any heat. 2. Transfer the estimated amount of hot coffee and cold milk into the foam cup. Click on the foam cup to read the temperature of its content. Make sure you will read the temperature with two decimal places within the information window (not the in the orange box). The information around the foam cup is not as accurate. Stockroom Information Name: Foam Cup Volume: 200.00 mL Temperature 650des pH: 6.42 1. If the temperature is exactly 65.00 °C, you are done with the lab. If the temperature is not exactly 65.00 °C, adjust the amount of coffee and milk to make the temperature approaches 65.00 °C while maintaining the total volume 200.0 mL, keep adjusting until 65.00 °C temperature is achieved. 2. Once you obtained the precise coffee, screen shot the information window showing the temperature 65.00 °C. Turn in the screen shot
Transcribed Image Text:Experimental procedure: 1. Place a bottle of hot coffee, a bottle of milk, and a 0.2L foam cup (in Glassware→Other) on the work bench. The foam cup is thermal insulating so it won't lose any heat. 2. Transfer the estimated amount of hot coffee and cold milk into the foam cup. Click on the foam cup to read the temperature of its content. Make sure you will read the temperature with two decimal places within the information window (not the in the orange box). The information around the foam cup is not as accurate. Stockroom Information Name: Foam Cup Volume: 200.00 mL Temperature 650des pH: 6.42 1. If the temperature is exactly 65.00 °C, you are done with the lab. If the temperature is not exactly 65.00 °C, adjust the amount of coffee and milk to make the temperature approaches 65.00 °C while maintaining the total volume 200.0 mL, keep adjusting until 65.00 °C temperature is achieved. 2. Once you obtained the precise coffee, screen shot the information window showing the temperature 65.00 °C. Turn in the screen shot
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