5. Based on the solved confidence intervals below, explain what affects the width of a confidence interval (the difference between the upper and lower limits) and how. M=20 o-10 N=30 95% CI-M+(1.96*OM) =20+(1.96*1.8257) 95% CI [16.42, 23.58] M-20 0-0.5 N=30 95% Cl=M±(1.96*ơu) =20+(1.96*0.0913) 95% CI [19.82, 20.18] M=20 o-10 N=500 95% CI-M+(1.96*OM) =20+(1.96*0.4472) 95% CI [19.12, 20.88] M=20 o-.5 N=500 95% Cl=M±(1.96*ơu) =20+(1.96*0.0224) 95% CI [19.96, 20.04]
5. Based on the solved confidence intervals below, explain what affects the width of a confidence interval (the difference between the upper and lower limits) and how. M=20 o-10 N=30 95% CI-M+(1.96*OM) =20+(1.96*1.8257) 95% CI [16.42, 23.58] M-20 0-0.5 N=30 95% Cl=M±(1.96*ơu) =20+(1.96*0.0913) 95% CI [19.82, 20.18] M=20 o-10 N=500 95% CI-M+(1.96*OM) =20+(1.96*0.4472) 95% CI [19.12, 20.88] M=20 o-.5 N=500 95% Cl=M±(1.96*ơu) =20+(1.96*0.0224) 95% CI [19.96, 20.04]
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
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![5. Based on the solved confidence intervals below, explain what affects the width of a
confidence interval (the difference between the upper and lower limits) and how.
M=20 o-10 N=30
95% Cl=M±(1.96*ơm)
=20+(1.96*1.8257)
95% CI [16.42, 23.58]
M=20 0-0.5 N=30
95% CI-M+(1.96*OM)
=20+(1.96*0.0913)
95% CI [19.82, 20.18]
M=20 o-10 N=500
95% CI=M+(1.96*OM)
=20+(1.96*0.4472)
95% CI [19.12, 20.88]
M=20 o=.5 N=500
95% CI-M+(1.96*OM)
=20+(1.96*0.0224)
95% CI [19.96, 20.04]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F789bf3e3-761b-4673-b549-67f9281d3551%2F78361796-8d4d-4e9e-826e-89d9017f3795%2Funualgd_processed.png&w=3840&q=75)
Transcribed Image Text:5. Based on the solved confidence intervals below, explain what affects the width of a
confidence interval (the difference between the upper and lower limits) and how.
M=20 o-10 N=30
95% Cl=M±(1.96*ơm)
=20+(1.96*1.8257)
95% CI [16.42, 23.58]
M=20 0-0.5 N=30
95% CI-M+(1.96*OM)
=20+(1.96*0.0913)
95% CI [19.82, 20.18]
M=20 o-10 N=500
95% CI=M+(1.96*OM)
=20+(1.96*0.4472)
95% CI [19.12, 20.88]
M=20 o=.5 N=500
95% CI-M+(1.96*OM)
=20+(1.96*0.0224)
95% CI [19.96, 20.04]
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