5. Auniform electric field with strength E= 5.40 × 10° N/C hits a closed hemisphere with radius R = 15.0 cm. The field enters the hemisphere perpendicular to the flat circular surface. The hemisphere encloses no charge. Find the electric flux through the flat circular surface. b. Find the electric flux through the curved surface. (Hint: There is a really easy way to do this!) a. R
5. Auniform electric field with strength E= 5.40 × 10° N/C hits a closed hemisphere with radius R = 15.0 cm. The field enters the hemisphere perpendicular to the flat circular surface. The hemisphere encloses no charge. Find the electric flux through the flat circular surface. b. Find the electric flux through the curved surface. (Hint: There is a really easy way to do this!) a. R
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5. A uniform electric field with strength E = 5.40 x 10° N/C hits a closed hemisphere with radius R = 15.0
cm. The field enters the hemisphere perpendicular to the flat circular surface. The hemisphere encloses
no charge.
Find the electric flux through the flat circular surface.
b. Find the electric flux through the curved surface. (Hint: There is a really easy way to do this!)
a.
IR](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fda2e0952-5073-44c4-aa37-c19a81cec12c%2Fa1c0900f-5924-47b1-8146-a0163e17be5e%2Fzeiblq4_processed.png&w=3840&q=75)
Transcribed Image Text:Updates Not Installed
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Update
5. A uniform electric field with strength E = 5.40 x 10° N/C hits a closed hemisphere with radius R = 15.0
cm. The field enters the hemisphere perpendicular to the flat circular surface. The hemisphere encloses
no charge.
Find the electric flux through the flat circular surface.
b. Find the electric flux through the curved surface. (Hint: There is a really easy way to do this!)
a.
IR
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