5. Assuming a 2's compliment implementation of ANSI C, which of the following lines of code will nerate an output of-32768. O Unsigned long int 1= 32768; printf("%d", 1);- O Unsigned short int k= 32768; printf("%d", k);- O Char m = 32768; printf("%d", m):- O Short int I= 32768; printf("%d", I);. O Long int j= 32768; printf("%d", j):- Which of the following statements correctly describe the associativity of the operators used in ANSI C? O Every operator has an associativity. O The associativity of an operator is either left-to-right or right-to-left. O Two different operators always have different associativity. O In the expression a =b = 5, the order of assignment is not decided by the associativity of the operators. O Associativity does not play a role unless the precedence of the operators is the same. Which of the following ANSI C functions correctly set the least significant n bits of x to 1 (one). aving all other bits unchanged. O void f(void) { int i; for (i=0;i

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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16. Assuming a 2's compliment implementation of ANSI C, which of the following lines of code will
generate an output of -32768.
O Unsigned long int 1 = 32768; printf("%d", 1);.
O Unsigned short int k = 32768; printf("%d", k);.
Char m = 32768; printf("%d", m);.
Short int I= 32768; printf("%d", I);.
O Long int j= 32768; printf("%d", j);.
4.Which of the following statements correctly describe the associativity of the operators used in ANSI C?
O Every operator has an associativity.
The associativity of an operator is either left-to-right or right-to-left.
O Two different operators always have different associativity.
In the expression a =b=5, the order of assignment is not decided by the associativity of the
operators.
O Associativity does not play a role unless the precedence of the operators is the same.
5.Which of the following ANSI C functions correctly set the least significant n bits of x to 1 (one),
leaving all other bits unchanged.
void f(void) { int i; for (i=0;i<n;++i) x ^=1«i; }
void f(void) { x F1«n; }
void f(void) { int i; for (i=0;i<n;++i) x|=1<i; }
void f(void) { x =-0 <<n; }
void f(void) { x =-(-0 ||x n; }
0000
Transcribed Image Text:16. Assuming a 2's compliment implementation of ANSI C, which of the following lines of code will generate an output of -32768. O Unsigned long int 1 = 32768; printf("%d", 1);. O Unsigned short int k = 32768; printf("%d", k);. Char m = 32768; printf("%d", m);. Short int I= 32768; printf("%d", I);. O Long int j= 32768; printf("%d", j);. 4.Which of the following statements correctly describe the associativity of the operators used in ANSI C? O Every operator has an associativity. The associativity of an operator is either left-to-right or right-to-left. O Two different operators always have different associativity. In the expression a =b=5, the order of assignment is not decided by the associativity of the operators. O Associativity does not play a role unless the precedence of the operators is the same. 5.Which of the following ANSI C functions correctly set the least significant n bits of x to 1 (one), leaving all other bits unchanged. void f(void) { int i; for (i=0;i<n;++i) x ^=1«i; } void f(void) { x F1«n; } void f(void) { int i; for (i=0;i<n;++i) x|=1<i; } void f(void) { x =-0 <<n; } void f(void) { x =-(-0 ||x n; } 0000
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