5. An equation of a circle is given by (x + 3)? + (y – 9)2 = 52. Apply the distributive property to the squared binomials and rearrange the equation so that one side is 0. (Lesson 6-5) %3D
5. An equation of a circle is given by (x + 3)? + (y – 9)2 = 52. Apply the distributive property to the squared binomials and rearrange the equation so that one side is 0. (Lesson 6-5) %3D
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.3: Parallel And Perpendicular Lines
Problem 4GP
Related questions
Question
![Topic Distances, Circles, and P
NAME
DATE
PERIOD
5. An equation of a circle is given by (x + 3)² + (y – 9)² = 5?. Apply the
distributive property to the squared binomials and rearrange the equation
so that one side is 0. (Lesson 6-5)
%3D
6. Respond to each question.
yA
a. Graph the circle
(x + 1)² + (y – 3)² = 16.
76
%3D
b. Find the distance from the
center of the circle to each point on
the list.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa5ae8a12-e3c6-4f21-bc3f-bfcaaa878716%2F5d9899ab-ba7f-416c-b0fe-87d106e5d6f2%2Fxcwjq6.jpeg&w=3840&q=75)
Transcribed Image Text:Topic Distances, Circles, and P
NAME
DATE
PERIOD
5. An equation of a circle is given by (x + 3)² + (y – 9)² = 5?. Apply the
distributive property to the squared binomials and rearrange the equation
so that one side is 0. (Lesson 6-5)
%3D
6. Respond to each question.
yA
a. Graph the circle
(x + 1)² + (y – 3)² = 16.
76
%3D
b. Find the distance from the
center of the circle to each point on
the list.
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