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- student found a bottle of unknown origin in the basement of an "CAUTION—contains С₁H₁O.” No other A old house. The bottle was labelled information was given, but inside the bottle were some white crystals. The student took the bottle to a chemistry laboratory, where she analyzed the crystals with the help of the laboratory staff. C₁2H₁6O reacted with Br₂ in CCl4 adding one mole of Br, and forming C₁₂H₁OB2₂. When a sample of C₁₂H₂O was reacted with O3 followed by Zn/H₂O, two different samples, J and K, were obtained. Compound J had a molecular formula of C.HgO₂, and its NMR is shown below. Compound K had a molecular formula of C₂H₂O, and it could be oxidized to compound L, with a molecular formula of C₂H₂O₂. The IR spectrum of L showed a very wide, strong band centred around 3000 cm*¹. The NMR spectrum of L showed only two different absorptions: a doublet (6H) at 0.9 ppm and a septet (1H) at 3.6 ppm. There was also a singlet (1H) off the scale at 11.8 ppm. students, deduce possible…Which practice is NOT used to gauge accuracy? raw data and results from calibration checks B. fortification recoveries (c quality control samples blank samples E sample replicationsYou have a 11.5 mg sample of blood that contains various proteins. Hemoglobin is the only protein in the sample containing Fe. Hemoglobin contains 3.83% by mass of a compound called heme (C₃₄H₃₂FeN₄O₄, MW = 616.49 g/mol). You find that your 11.5 mg blood sample contains 34.9 micrograms of Fe. What is the mass percent of hemoglobin in your protein sample? -don't prematureley round
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