5. Again following on from the previous question, suppose it is known tha when we take a random sample of n = 61 STM1001 students, the probability that the sample mean is less than some number is 0.6. What must be?
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- Solve question 1 last part b where the question states... Probability that the total amount of time required to make an oil change in all cars from the sample of 100 cars is more than 3500 minutes is________2Is the national crime rate really going down? Some sociologists say yes! They say that the reason for the decline in crime rates in the 1980s and 1990s is demographics. It seems that the population is aging, and older people commit fewer crimes. According to the FBI and the Justice Department, 70% of all arrests are of males aged 15 to 34 years†. Suppose you are a sociologist in Rock Springs, Wyoming, and a random sample of police files showed that of 33arrests last month, 25were of males aged 15 to 34 years. Use a 1%level of significance to test the claim that the population proportion of such arrests in Rock Springs is different from 70%. a. What is the level of significance? answer .01 b.State the null and alternate hypotheses. Which one? Its the third. H0: p< 0 .7; H1: p= 0.7 H0: p≠0.7; H1: p= 0.7 H0: p= 0.7; H1: p≠0.7 H0: p= 0 .7; H1: p< 0.7 H0: p= 0.7; H1: p> 0.7 c. What sampling distribution will you use? Its the last one. The Student's t, since np> 5 and…
- Question #11For a standardized psychology examination intended for psychology majors, the historical data show that scores have a mean of 515 and a standard deviation of 175. The grading process of this year's exam has just begun. The average score of the 40 exams graded so far is 518. What is the probability that a sample of 40 exams will have a mean score of 518 or more if the exam scores follow the same distribution as in the past? Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places. Sub ContinueSolve normal distribution problem #11
- Is the national crime rate really going down? Some sociologists say yes! They say that the reason for the decline in crime rates in the 1980s and 1990s is demographics. It seems that the population is aging, and older people commit fewer crimes. According to the FBI and the Justice Department, 70% of all arrests are of males aged 15 to 34 years†. Suppose you are a sociologist in Rock Springs, Wyoming, and a random sample of police files showed that of 34 arrests last month, 27 were of males aged 15 to 34 years. Use a 10% level of significance to test the claim that the population proportion of such arrests in Rock Springs is different from 70%. State the null and alternate hypotheses. H0: p = 0 .7; H1: p < 0.7 H0: p ≠ 0.7; H1: p = 0.7 H0: p < 0 .7; H1: p = 0.7 H0: p = 0.7; H1: p ≠ 0.7 H0: p = 0.7; H1: p > 0.7 What sampling distribution will you use? The standard normal, since np > 5 and nq > 5. The standard normal, since np < 5 and nq < 5. The Student's…2. Suppose X is a normally distributed random variable with a mean of 9.00. If the probability that X is less than 9.66 is 0.67, then what is the standard deviation of X?Please
- Question 5 > About 62% of people who are murdered knew the person who committed the murder. Suppose that Detective Moore's case load currently has 50 unsolved murders. Use a normal distribution approximation to the binomial distribution to find the following probabilities: a. What is the probability that no more than 28 of the victims among Detective Moore's case files knew their murderer? b. What is the probability that between 28 and 34 of the victims knew their murderer?8.Suppose Jack and Diane are each attempting to use a simulation to describe the sampling distribution from a population that is skewed right with mean 60 and standard deviation 5. Jack obtains 1000 random samples of size n=5 from the population, finds the mean of the means, and determines the standard deviation of the means. Diane does the same simulation, but obtains 1000 random samples of size n=30 from the population What do you expect the mean of Jack's distribution to be? What do you expect the mean of Diane's distribution to be?