5. A uniform rod 4-kg in mass and 5-m in length is balanced on a triangular pivot that is 2-m from the left-end of the rod. Two masses are then hung on the rod: a 12-kg block that is on the left-end of the rod; and a 4- kg block that is on the right-end of the rod. Where should and additional 5-kg mass be placed to balance out the system as shown below? 5-m long rod; 4-kg in mass 12-kg 2-m x=? 3-m 4-kg 5-kg
5. A uniform rod 4-kg in mass and 5-m in length is balanced on a triangular pivot that is 2-m from the left-end of the rod. Two masses are then hung on the rod: a 12-kg block that is on the left-end of the rod; and a 4- kg block that is on the right-end of the rod. Where should and additional 5-kg mass be placed to balance out the system as shown below? 5-m long rod; 4-kg in mass 12-kg 2-m x=? 3-m 4-kg 5-kg
Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter14: Static Equilibrium, Elasticity, And Fracture
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Transcribed Image Text:5. A uniform rod 4-kg in mass and 5-m in length is balanced on a triangular pivot that is 2-m from the left-end
of the rod. Two masses are then hung on the rod: a 12-kg block that is on the left-end of the rod; and a 4-
kg block that is on the right-end of the rod. Where should and additional 5-kg mass be placed to balance
out the system as shown below?
5-m long rod; 4-kg in mass
12-kg
2-m
x=?
3-m
4-kg
5-kg
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