**Problem:**A specimen of aluminum (Al) has a cross-sectional area of 10×12.7 mm² and is subjected to a pulling force of 35,500 N, resulting in elastic deformation. Calculate the strain produced. (Aluminum elastic modulus = 69 GPa)**Solution:**To find the strain, use the formula:Strain (ε) = Stress / Elastic Modulus (E)1. **Calculate the cross-sectional area (A):** \( A = 10 \, \text{mm} \times 12.7 \, \text{mm} = 127 \, \text{mm}^2 = 1.27 \times 10^{-4} \, \text{m}^2 \)2. **Calculate the stress (σ):** \( \text{Stress (σ)} = \frac{\text{Force (F)}}{\text{Area (A)}} = \frac{35,500 \, \text{N}}{1.27 \times 10^{-4} \, \text{m}^2} \)3. **Use the elastic modulus (E):** Given \( E = 69 \, \text{GPa} = 69 \times 10^9 \, \text{Pa} \)4. **Calculate the strain (ε):** \( \text{Strain (ε)} = \frac{\text{Stress (σ)}}{E} \)Inserting the values and solving these equations will give the result for the strain.

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5. A specimen of Al have a cross section 10×12.7 mm?, pulled with 35,500N, producing elastic deformation, calculate strain. (Al elastic modulus 69GPA)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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**Problem:**

A specimen of aluminum (Al) has a cross-sectional area of 10×12.7 mm² and is subjected to a pulling force of 35,500 N, resulting in elastic deformation. Calculate the strain produced. (Aluminum elastic modulus = 69 GPa)

**Solution:**

To find the strain, use the formula:

Strain (ε) = Stress / Elastic Modulus (E)

1. **Calculate the cross-sectional area (A):**

\( A = 10 \, \text{mm} \times 12.7 \, \text{mm} = 127 \, \text{mm}^2 = 1.27 \times 10^{-4} \, \text{m}^2 \)

2. **Calculate the stress (σ):**

\( \text{Stress (σ)} = \frac{\text{Force (F)}}{\text{Area (A)}} = \frac{35,500 \, \text{N}}{1.27 \times 10^{-4} \, \text{m}^2} \)

3. **Use the elastic modulus (E):**

Given \( E = 69 \, \text{GPa} = 69 \times 10^9 \, \text{Pa} \)

4. **Calculate the strain (ε):**

\( \text{Strain (ε)} = \frac{\text{Stress (σ)}}{E} \)

Inserting the values and solving these equations will give the result for the strain.

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