5. A solid steel disk E-200x10^9 N/m^2 start rotation from the rest with constant acceleration. When the disk changed an angular position by 180 degrees, a small disk attachment (hummer) hit an aluminum rodE= 70 x 10^9 N/m^2. At that moment the angular velocity was 2500 rad/s. Diameter of the aluminum rod is 0.1 m. Please, find strain in the rod. R= 2m Rad Wo =O- lad A- d: 0,!m Wi= 2500 hummer AC

Elements Of Electromagnetics
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5. A solid steel disk E-200X10^9 N/m^2 start rotation from the rest with constant acceleration. When
the disk changed an angular position by 180 degrees, a small disk attachment (hummer) hit an
aluminum rod E = 70 x 10^9 N/m^2. At that moment the angular velocity was 2500 rad/s. Diameter of
the aluminum rod is 0.1 m. Please, find strain in the rod.
R= 2m
Rad
A- - -
d= 01 m
hummer
%3D
Al
Transcribed Image Text:5. A solid steel disk E-200X10^9 N/m^2 start rotation from the rest with constant acceleration. When the disk changed an angular position by 180 degrees, a small disk attachment (hummer) hit an aluminum rod E = 70 x 10^9 N/m^2. At that moment the angular velocity was 2500 rad/s. Diameter of the aluminum rod is 0.1 m. Please, find strain in the rod. R= 2m Rad A- - - d= 01 m hummer %3D Al
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