5. A sample of 0.6 kg of water at 90°C is placed in a container with 0.6 kg of water at 5 "C. After the water comes to thermal equilibrium. A 0.2 kg sample of tin at 20°C is then placed in the container. What will be the new temperature of the mixture? Use C = 4182 J/kgK for the specific heat of water and use C = 210 J/kgK for the specific heat of tin. *
5. A sample of 0.6 kg of water at 90°C is placed in a container with 0.6 kg of water at 5 "C. After the water comes to thermal equilibrium. A 0.2 kg sample of tin at 20°C is then placed in the container. What will be the new temperature of the mixture? Use C = 4182 J/kgK for the specific heat of water and use C = 210 J/kgK for the specific heat of tin. *
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Transcribed Image Text:5. A sample of 0.6 kg of water at 90°C is placed in a container with 0.6 kg
of water at 5 "C. After the water comes to thermal equilibrium. A 0.2 kg
sample of tin at 20°C is then placed in the container. What will be the new
temperature of the mixture? Use C = 4182 J/kgK for the specific heat of
water and use C = 210 J/kgk for the specific heat of tin.*
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