5. A negative point charge moves through the region with uniform electric and magnetic fields shown whose magnitudes are 10.0 N/C and 0.10 T respectively. If the electron is initially moving with a velocity 100 m/s downward, which of the following statements is TRUE regarding the velocity of the charge in this region? Neglect air resistance, gravity, and friction. b. A The final velocity is still 100 m/s directed downwards. B. The final velocity is less than 100 m/s directed downwards. C. The final velocity is greater than 100 m/s directed to the right. D. The final velocity is still 100 m/s directed to the left. E. The final velocity is greater than 100 m/s directed to the left.

5. A negative point charge moves through the region with uniform electric and magnetic fields shown whose magnitudes are 10.0 N/C and 0.10 T respectively. If the electron is initially moving with a velocity 100 m/s downward, which of the following statements is TRUE regarding the velocity of the charge in this region? Neglect air resistance, gravity, and friction. b. A The final velocity is still 100 m/s directed downwards. B. The final velocity is less than 100 m/s directed downwards. C. The final velocity is greater than 100 m/s directed to the right. D. The final velocity is still 100 m/s directed to the left. E. The final velocity is greater than 100 m/s directed to the left.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A proton is traveling through a region of space containing both a magnetic and electric field. At one instant in time, the velocity is U = (13500 Î + +38500) m/s and the acceleration is a = (4.39 k) x 10 m/s². If B=(9.21 k) mT, what is the magnitude of the electric field? i Save for Later N/C Submit Answer
A velocity selector in a mass spectrometer, like the one shown below, uses a 0.133 T magnetic field.a. What electric field strength is needed to select a speed of 4.93*10^6 m/s?b. What is the voltage between the plates if they are separated by 1.00 cm?
1. A magnetic field has a magnitude of 1.50 × 10-³ T, and an electric field has a magnitude of 4.00 × 10³ N/C. Both fields -3 point in the same direction. A positive 2.5 µC charge moves at a speed of 2.50 × 106 m/s in a perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. N ssfánection that is 0 ssf60 sf60 ss 50 ssf6 €60 ssf60 ss
A charged particle moves through a velocity selector at constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude E = 1.50 x 104 N/C and B = 0.4 T. %3D Hint a. What is the velocity of the charged particle? Velocity of the charged particle is x 104 m/s. b. When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at B = 0.4 T). What is the mass-to-charge ratio of the particle? Hint for (b) Mass-to-charge ratio of the part is kg/C. (Use the "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10´ 12".) - 12 enter "3.14E-