5. A manometer with arms of unequal diameters have cross sectional areas of 10 cm² and 5 cm², respectively. Its both ends are open to the atmosphere and contains mercury (specific gravity 13.6): see sketch below. 50 cm³ of water, which is immiscible with mercury, is added into the right arm with the smaller cross sectional area. Calculate the rise in the mercury level in the left arm (i.e., the arm with the larger diameter). 50 cm³ Ap= pgh Patm 10 cm² Find Pressure here = pressure balance of hydrostatic pressure d ( use these pressure to fond Sem 10cm depth of 10 cm (10cm colono noter)

5. A manometer with arms of unequal diameters have cross sectional areas of 10 cm² and 5 cm², respectively. Its both ends are open to the atmosphere and contains mercury (specific gravity 13.6): see sketch below. 50 cm³ of water, which is immiscible with mercury, is added into the right arm with the smaller cross sectional area. Calculate the rise in the mercury level in the left arm (i.e., the arm with the larger diameter). 50 cm³ Ap= pgh Patm 10 cm² Find Pressure here = pressure balance of hydrostatic pressure d ( use these pressure to fond Sem 10cm depth of 10 cm (10cm colono noter)

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Description: 5. A manometer with arms of unequal diameters have cross sectional areas of 10 cm² and 5cm², respectively. Its both ends are open to the atmosphere and contains mercury (specificgravity 13.6): see sketch below. 50 cm³ of water, which is immiscible w

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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