5. *A charge Q₁ = +3 µC is located at (-5 cm, 0) while charge Q2 = -4 μC is located at (0, +5 cm). These are the two white charges in the diagram at right. a. What is the electric field at the origin (0, 0) due to these two charges? Q₂=-4 μCL Q₁ = 3 μC 5 cm b. If a third charge of 5 µC (the gray charge) is placed at the point (-4 cm, 3 cm), what will now be the electric field at the origin? 5 cm
5. *A charge Q₁ = +3 µC is located at (-5 cm, 0) while charge Q2 = -4 μC is located at (0, +5 cm). These are the two white charges in the diagram at right. a. What is the electric field at the origin (0, 0) due to these two charges? Q₂=-4 μCL Q₁ = 3 μC 5 cm b. If a third charge of 5 µC (the gray charge) is placed at the point (-4 cm, 3 cm), what will now be the electric field at the origin? 5 cm
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Question
Transcribed Image Text:5. *A charge Q₁ = +3 µC is located at (-5 cm, 0) while charge
Q₂ = -4 μC is located at (0, +5 cm). These are the two white
charges in the diagram at right.
a. What is the electric field at the origin (0, 0) due to these
two charges?
b.
If a third charge of 5 µC (the gray charge) is placed at
the point (-4 cm, 3 cm), what will now be the electric field at the origin?
Q₁ = 3 μC ¦
5 cm
5 cm
Expert Solution
Introduction:
We are given 2 charges at x and y axes respectively. We find electric field at the origin due to these charges. We then find the electric field due to third charge and hence the net field at origin. We resolve the components of electric field and hence give the field in component form.
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Follow-up Questions
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Follow-up Question
How did the I in Enet change? Wouldn't it be 2.88i? I'm not getting it...
Additionally what is with 4/5 i * E' x 3/5 j E'?
Solution
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