The electric flux through each of the six sides of arectangular box are as follows 4 =155 3N-m/C, 4 = 236 4 N.m/C =-334 3N.m/C ,-173 8 N.m/C 4--1118N.m²/C d= 448 0 N m²/C.V Part AHow much charge is in this box?PCSubmitPrevious Answers Request Answer* Incorrect Try Again; 5 attempts remaining

Given: Electric flux through each side of a rectangular box is: ϕ1=155.3 N.m2/Cϕ2=236.4…

The electric flux through each of the six sides of a rectangular bOx are as followS 4 - 155 3. N-m/C - 236 4 N.m²/C = -334 3 N.m²/C 4-1738 N m/C &--111 8 N. m/C d = 448 0 N- m²/C V Part A How much charge is in this box? Q- pC

The electric flux through each of the six sides of a rectangular bOx are as followS 4 - 155 3. N-m/C - 236 4 N.m²/C = -334 3 N.m²/C 4-1738 N m/C &--111 8 N. m/C d = 448 0 N- m²/C V Part A How much charge is in this box? Q- pC

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Chapter1: Units, Trigonometry. And Vectors

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The electric flux through each of the six sides of a
rectangular box are as follows 4 =155 3
N-m/C, 4 = 236 4 N.m/C =-334 3
N.m/C ,-173 8 N.m/C 4--1118
N.m²/C d= 448 0 N m²/C.
V Part A
How much charge is in this box?
PC
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