#5 D. The spE. None of the above.4. A box that weighs 300 N is pulled across a level surface with a constant velocity. The rope makes aangle of 30.0 degrees above the horizontal and the tension in the rope is 100 N. What is the normalforce of the floor on the box?A. 86 NB. 300 NC. 50 ND. 250 NE. ONB. 450 NC. 750 ND. 550 NE. 440 NLOON300not100 ros 3086.6->100 30-50 ↑fg=300N5. A 750 N box rests on a floor with a coefficient of static friction = 0.800 and coefficient of kineticfriction=0.600. What is the force of friction if a horizontal force of 550 N is applied to the box?A. 600 NFN = 750 NF₁-750=0FN=7501,2-FN +50-300-0 F = 250NN> F₁ = 550 WVFG:750N6. Explain the fact that static friction force changes as you increase the applied force.When an object has no acceleration, the forcesoffset eachother. Therefore,anystatic friction does as well, until itfriction, inisfsmax = 750.8= 606sultates IS K U.4tension on the rope.550 4600,theremovon the x axiapplied force increasetime anpasses the maximum st.which case the friction becomes kinetic, and thezerG.e acceleration of une doxes and10. When system is in motion, find the acceleration and the tens

Answered: Image /qna-images/answer/7c781595-0cc8-4dbd-a5ab-e6345bf51e95.jpg

5. A 750 N box rests on a floor with a coefficient of static friction = 0.800 and coefficient of kinetic What is the force of friction if a horizontal force of 550 N is applied to the box? FN=750 N friction=0.600. A. 600 N B. 450 N C. 750 N D.550 N E. 440 N f<- > F₁ = 550 W VF g = =7500 F₁-750=0 FN=750 N fsmax = 750.8 = 606