5. A 250-volt electrical heater is used to warm 3Li/hr of water from 19°C to 98°C. Assume heat conversion loss of 25% of the total heat supplied, how much current in amperes must be supplied to this heater. Derive with the formula below, show the cancellation, explain the step by step and DRAW a free body diagram/figure. refer with this: PE1 + KE1 + U1 + WF1 + Q1 + W1 = PE2 + KE2 + U2 + WF2 + Q2 + W2 + E losses.
5. A 250-volt electrical heater is used to warm 3Li/hr of water from 19°C to 98°C. Assume heat conversion loss of 25% of the total heat supplied, how much current in amperes must be supplied to this heater. Derive with the formula below, show the cancellation, explain the step by step and DRAW a free body diagram/figure. refer with this: PE1 + KE1 + U1 + WF1 + Q1 + W1 = PE2 + KE2 + U2 + WF2 + Q2 + W2 + E losses.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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5. A 250-volt electrical heater is used to warm 3Li/hr of water from 19°C to 98°C. Assume heat conversion loss of 25% of the total heat supplied, how much current in amperes must be supplied to this heater.
Derive with the formula below, show the cancellation, explain the step by step and DRAW a free body diagram/figure.
refer with this:
PE1 + KE1 + U1 + WF1 + Q1 + W1 = PE2 + KE2 + U2 + WF2 + Q2 + W2 + E losses.
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