5. 3-bromo-1-phenyl-1-propene (below) shows a complex NMR spectrum in which the vinylic proton at C2 is coupled with both the C1 vinylic proton (J = 16 Hz) and the C3 methylene protons (J = 8 Hz). Draw a tree diagram for the C2 proton signal, and account for the fact that a five-line multiplet is observed. C1 C2 L CH₂Br H C3
5. 3-bromo-1-phenyl-1-propene (below) shows a complex NMR spectrum in which the vinylic proton at C2 is coupled with both the C1 vinylic proton (J = 16 Hz) and the C3 methylene protons (J = 8 Hz). Draw a tree diagram for the C2 proton signal, and account for the fact that a five-line multiplet is observed. C1 C2 L CH₂Br H C3
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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
Transcribed Image Text:**Problem 5: NMR Spectrum Analysis of 3-Bromo-1-phenyl-1-propene**
**Objective:**
To analyze the 3-Bromo-1-phenyl-1-propene compound, particularly focusing on the proton (H) attached to carbon 2 (C2) in the complex NMR spectrum. This proton is coupled with both the vinylic proton at carbon 1 (C1) with a coupling constant \(J = 16 \text{ Hz}\) and the methylene protons at carbon 3 (C3) with a coupling constant \(J = 8 \text{ Hz}\). The goal is to draw a tree diagram for the C2 proton signal and account for the five-line multiplet that is observed.
**Structure of 3-Bromo-1-phenyl-1-propene:**
The compound is illustrated as follows:
- A benzene ring (phenyl group) attached to C1.
- C1 is bonded to a hydrogen (H).
- C2 is bonded to a hydrogen (H) and CH2Br group.
- C3 is bonded to two hydrogens (\(CH_2\)) and a bromine (Br).
**NMR Coupling Explanation:**
1. The vinylic proton at C2 experiences spin-spin coupling with the proton at C1 (with \(J = 16 \text{ Hz}\)).
2. The same vinylic proton at C2 also couples with the two protons in the methylene group at C3 (with \(J = 8 \text{ Hz}\)).
Since there are two sets of couplings, the C2 proton signal will be split by the C1 proton and further split by the C3 protons, leading to a complex pattern observed in the NMR spectrum.
**Tree Diagram:**
The tree diagram is used to illustrate the splitting pattern of the proton signals due to coupling:
- **First Splitting (due to C1 proton, \(J = 16 \text{ Hz}\)):**
- The signal starts as a single peak.
- This peak is split into a doublet by the coupling with the adjacent C1 proton.
- **Second Splitting (due to C3 protons, \(J = 8 \text{ Hz}\)):**
- Each line of the initial doublet further splits into a triplet due to the
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