5. 1.02 g of Mg was reacted with excess 1 M HCI(ag) (255.0 g) in a coffee-cup calorimeter. Tsoln rose from 22.0 °C to 41.6°C. Calculate the AHon of this reaction, Gici = 3.90 J g-1°C-1 ans: -466 kJ/mol A8S8950 lution=mcATWolict enimmetsb of woled riine noitoser biebnste erl eaU
The question I need help with is #5 on the attached image. How do I calculate the change in heat using the given information in #5? I have tried multiple times and cannot figure out what to do. My professor provided the final answer (-466kJ), but I need help getting to that answer. Thanks.
We know ,
q(HCl) = m×c×(t2-t1) where t2 = final temperature
Given m = 255 gm t1 = initail temperature
c = 3.90 j.g-1 c -1
t2= 41.6 c
t1 = 22.0 c
Now
q(HCl) = m×s×(t2-t1)
= 255 gm × 3.90 j.gm-1 c -1×(41.6-22.0) c
= 19492.2 j
q(reaction) = - q(HCl) = -19492.2 j
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