1. A metal weighing 30 g absorbs 200.0 J of heat when its temperature increases by 80.0°C. What is the specific heat capacity of the metal? c=J/g°C c=200J/ (30g)(80°C) = 0.083J/g °C Therefore the specific heat capacity of the metal is 0.083J/g°C 2. Calculate the mass (in grams) of iron that could be warmed from 20°C to 65°C by applying 4.5 kJ of energy. The specific heat capacity of iron is 0.45 J/g•°C. 4.5kJ = 4,500 J q = mcΔT m = 4,500 J(0.45J/g°C)(65°C - 20°C)
Hi there, I was working through some questions and want to know if I am doing them right, there was no answer sheet attached to the practice questions and just want to make sure I understand how to do these types of questions
1. A metal weighing 30 g absorbs 200.0 J of heat when its temperature increases by 80.0°C. What is the specific heat capacity of the metal?
c=J/g°C
c=200J/ (30g)(80°C)
= 0.083J/g °C
Therefore the specific heat capacity of the metal is 0.083J/g°C
2. Calculate the mass (in grams) of iron that could be warmed from 20°C to 65°C by applying 4.5 kJ of energy. The specific heat capacity of iron is 0.45 J/g•°C.
4.5kJ = 4,500 J
q = mcΔT
m = 4,500 J(0.45J/g°C)(65°C - 20°C)
m = 222g
Therefore the mass of iron is 222g
3. How much heat in kilojoules is released when 500.0 g of water is cooled from 85.0ºC to 10.0ºC? The specific heat capacity of water is 4.184 J/(g•°C).
q = mcΔT
q = (500g)(4.184 Jg°C) (10ºC - 85ºC)
= -156,900 kJ
Therefore the amount of heat released is -156,900kJ
4. If 2200 J of heat is absorbed by a sample of iron weighing 50.0 grams, how many degrees would its temperature change? The specific heat capacity of iron is 0.45 J/g•°C.
q = mcΔT
ΔT = 2,200J/ (50g)(0.45J/g°C)
ΔT = 98°C
Therefore the temperature change is 98°C
5. The specific heat capacity of diamond is 0.509 J/g•°C, and 5000 J of energy is required to heat a 50 g sample of diamond to a final temperature of 98°C. What was the sample's initial temperature?
q = mcΔT
ΔT = 5000 J(50g)(0.509J/g°C)
ΔT = 196°C - 98°C
ΔT = 98°C
Therefore the sample's initial temperature was 98°C which is the same as the final temperature, this means that there was no change of temperature in the diamond sample.
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